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adell [148]
3 years ago
13

Cds are packaged in boxes of 90. every 28 boxes are loaded onto a crate. how many crates would be needed if you had 260000 cdsto

pack?
Mathematics
1 answer:
KatRina [158]3 years ago
8 0
So there are 90 Cd's in each box correct. And there are 260000 Cd's to pack. For you to figure out you would need to divide the number of Cd's by 90. Then divide that number you get by 28. Your answer would be a decimal.
Hope this helps:)
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What is the area of the rhombus
erastova [34]

Answer:

12

Step-by-step explanation:

3 0
3 years ago
How to solve <br> -8x-5+3x=7+4x-9
frez [133]

Answer:

-1/3

Step-by-step explanation:

-8x-5+3x=7+4x-9

-5x-5=7+4x-9

-5x-4x-5=7-9

-9x-5=-2

-9x=-2+5

-9x=3

x=3/-9

x=-1/3

6 0
3 years ago
The percentage of water in an unknown hydrate was determined by heating the sample and driving the water off the sample. Two ind
Bas_tet [7]

Answer:

It should be reported as 20.648%

Step-by-step explanation:

Since we have 2 different observed values hence we shall use an average of the 2 values to report the result

Thus value is \frac{19.564+21.731}{2}=20.6475%

As we can see that the least count of our observations is upto 3 decimal places hence we have to report a result upto only 3 decimal places thus we need to round off the fourth decimal place thus the digit shall be increased by 1 since we have to drop off 5 and the digit before 5 is 7 which is an odd number.

Thus the result shall be 20.648%

8 0
3 years ago
First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
3 years ago
An object launched vertically from a point that is 37.5 feet above ground level with an initial velocity of 48.6 feet per second
Elis [28]

Answer: 3.675 seconds

Step-by-step explanation:

Hi, when the object hits the ground, h=0:

h=−16t^2+48.6t+37.5

0=−16t^2+48.6t+37.5

We have to apply the quadratic formula:  

For: ax2+ bx + c  

x =[ -b ± √b²-4ac] /2a  

Replacing with the values given:  

a=-16 ; b=48.6; c=37.5

x =[ -(48.6) ± √(-48.6)²-4(-16)37.5] /2(-16)  

x = [ -48.6 ± √ 4,761.96] /-32

x = [ -48.6 ± 69] /-32

Positive:  

x = [ -48.6 + 69] /-32 = -0.6375

Negative:  

x = [ -48.6 - 69] /-32 = 3.675 seconds (seconds can't be negative)

Feel free to ask for more if needed or if you did not understand something.  

8 0
3 years ago
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