Answer:
a. True, b. False, c.True, d. True
Explanation:
a. Base excision repair is started by a DNA glycosylase that recognizes the changes and removes the altered base by cleavage of the glycosidic bond binding the base and the deoxyribose sugar together.
b. Nucleotide excision repair works by a cut-and patch mechanism that removes their heavy lesions, including pyrimidine dimers and nucleotides . Endonucleases are responsible for the lesion of the damaged strand.
c. Nucleotide excision repair is initiated by the proteins namely UvrA, UvrC, and UvrB in Escherichia coli.
-UvrD (helicase II) later removes the damaged strand
-DNA polymerase I (PolI) fills in the resulting gap.
d. DNA glycolases removes the damaged nitrogenous base.
-It leaves the sugar-phosphate backbone intact and thus creating an apurinic/apyrimidinic site, which is commonly referred to as an AP site.
e. Xeroderma pigmentosum complementation group A(XPA)
-This is an essential protein in the nucleotide excision repair pathway.
- It helps to make a pre-incision complex along with other proteins.
Traditional forms shows the evolutionary steps between species
I believe the answer your looking for is precipitation cycle
The distributions of individual intron<span> (</span>intron length<span> distribution) and </span>exon<span> ... We also</span>used<span> the general databases of 10 model species for similar analysis for the ... An</span>average gene<span> contains 3.7 </span>introns<span> in 1 kb of protein </span>coding region, but with .... ofintron sizes<span> in Figure 1 implies that very large </span>introns<span> may </span>make<span> up a small </span>
