(2/3)x = 10
(3/2)(2/3)x = 10(3/2)
x = 30/2 = 15
Let's call the three numbers x, y, and z.
The numbers are 3, 12, and 5.
x + y + z = 20
y = 4x
x + z = 8
We can rewrite the first equation because y is 4x, so
x + 4x + z = 20
5x + z = 20
And now we can use simultaneous equation rules to solve
5x + z = 20
x + z = 8
5x + z = 20
5x + 5z = 40
(subtract)
-4z + -20
÷ -4
z = 5
x + z = 8
x + 5 = 8
x = 3
y = 4x
y = 4 × 3
y = 12
I hope this helps!
It would be nonsense, as if the beetle were at normal size, then it would be considered 1/1 as a scale. If you wanted to increase it, you would increase the numerator.
For this case, the first thing you should do is take into account the irrational number definition.
An irrational number is one that can not be written as the quotient between two whole numbers.
Their number of decimals is unlimited and they are not periodic.
An irrational number within the specified domain is:
π/2 = 1.570796327
Answer:
an example of an irrational number that is less than 2 and greater than 1.5 is:
π/2 = 1.570796327
The width of the court is 30 feet!
