Using the distributive property , 4*9+4*7 or 36+28
No, the centroid and Circumcentre are not same but it is same in equilateral triangle.
The intersection of a triangle's perpendicular bisectors is called the circumcenter.A triangle's circumcenter is a location that is equally spaced from each of its vertices.The centroid of a triangle is the location where its medians connect.
Triangle's centroid is always within it. The centroid of a triangle is its center of gravity in physical terms. If the triangle is evenly distributed around the plane's surface and you want to balance it by supporting it at only one point, you must do it near the center of gravity.Are the circumcenter and centroid at the same location? In the case of an equilateral triangle, they will both be.
Therefore, the centroid and Circumcentre are not same but it is same in equilateral triangle.
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Answer:
17
Step-by-step explanation:
I would just solve them individually for 3 and then add them together. f(x)=6(3)+3 = 21 and g(x)= 3-7= -4
(f+g)(3) = 21-4= 17
Answer:
The first option is not a direct variation
Step-by-step explanation:
When we talk of a direct variation, as one value increases, the other value increases too
Or as one value decreases, the other value decreases
A direct variation is of the form;
y = kx
k = y/x
where k is the coefficient of variation that must be a constant value all through the set of values
The values we are comparing here are the x and y values
So
let us take a look at the options;
The first option is not a direct variation
For the first option, the rate of increase is not constant;
2/6 = 1/3 , 8/12 = 2/3 , 14/18 = 7/9
for the second;
the ratio is 1 to 1
for the third;
3/6 = 1/2 ; 6/12 = 1/2; 9/18 = 1/2
for the fourth;
2/6 = 1/3, 4/12 = 1/3 , 6/18 = 1/3
Answer:
x = 3 + √6 ; x = 3 - √6 ; 
; 
Step-by-step explanation:
Relation given in the question:
(x² − 6x +3)(2x² − 4x − 7) = 0
Now,
for the above relation to be true the following condition must be followed:
Either (x² − 6x +3) = 0 ............(1)
or
(2x² − 4x − 7) = 0 ..........(2)
now considering the equation (1)
(x² − 6x +3) = 0
the roots can be found out as:
for the equation ax² + bx + c = 0
thus,
the roots are
or
or
and, x = 
or
and, x = 
or
x = 3 + √6 and x = 3 - √6
similarly for (2x² − 4x − 7) = 0.
we have
the roots are
or
or
and, x = 
or
and, x = 
or
and, x = 
or
and,
Hence, the possible roots are
x = 3 + √6 ; x = 3 - √6 ; ;
