Ask question

Ask question

All categories

3 years ago

6

Suppose $2000 is deposited in an account paying 2.5% interest compounded quarterly. What will the account balance be after 12 ye

ars?

1 answer:

IrinaVladis [17]3 years ago

6 0

A=p(1+i/m)^mn
A=2000(1+0.025/4)^4*12
A=2,697.2

You might be interested in

What is the degree of the polynomial?

timurjin [86]

Answer:

Polynomial is the degree of the highest degree of polynomial form.

Number

0

is also called a polynomial and it has no degree

6 0

3 years ago

Read 2 more answers

5. Write an equivalent expression for (2x + 4)(x-5)

vfiekz [6]

$2x^{2} -10x +4x -20$

I'm not sure if you need to simplify

8 0

3 years ago

Read 2 more answers

Draw a figure to fit each description.

antiseptic1488 [7]

1)
a) Draw the axis:x-axis is horizontal, y-axis is vertical
b) draw a point on any part of the plane (use color to highlight it)
c) draw a second point on a different part of the plane (again use color)
d) draw the straight line that passes through the two points (use a ruler).

That is it.

2)
a) Draw the axis: x-axis is horizontal and y-axis is vertical
b) Draw a stright line (use a ruler)
c) Draw a second straight line (use a ruler) which is not parallel to the first line. Extend the second line intil it intersects (and passes) the first line. The lines can only intersect in one point (if the lines are parallel they will not intersect each other).

6 0

3 years ago

I just need a little help figuring this out<br><br>find the value of X<br>

Hitman42 [59]

X=70... do u need an explanation?

5 0

3 years ago

A community bird-watching society makes and sells simple bird feeders to raise money for its conservation activities. The materi

blondinia [14]

Answer:

The required function is: $P(x)=-3x^2+78x-360$

The price for each feeder to maximize profit should be $13.

The maximum weekly profit is $147

Step-by-step explanation:

Consider the provided information.

Part (A)

The materials for each feeder cost $6, and the society sells an average of 30 per week at a price of $10 each.

Let x be the price per feeder.

Profit = Revenue - cost

So the profit per feeder is $x-6$

If we increase then for every dollar increase, it loses 3 sales per week.

This can be written as:

$30-3(x-10)$

$30-3x+30$

$-3x+60$

Where x-10 represents the increase in price and 3 represents the decrease in sales per week.

Thus the profit will be:

$P(x)=(x-6)(-3x+60)$

$P(x)=-3x^2+78x-360$

Hence, the required function is: $P(x)=-3x^2+78x-360$

Part (B) What price should the society charge for each feeder to maximize profits? What is the maximum weekly profit?

The above function is a downward parabola so the maximum will occur at vertex.

The x coordinate of the vertex of parabola is: $x=\frac{-b}{2a}$

Substitute a=-3, b=78 and c=-360 in above.

$x=\frac{-78}{2(-3)}=13$

Hence, the price for each feeder to maximize profit should be $13.

Now substitute the value of x in $P(x)=-3x^2+78x-360$

$P(x)=-3(13)^2+78(13)-360=$147$

Hence, the maximum weekly profit is $147

5 0

3 years ago