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True [87]
3 years ago
8

What is a non-example of an inverse relationship

Physics
1 answer:
Scilla [17]3 years ago
6 0
Savings is inversely related to expenditure when the income is constant. <span>A more technical example is current is inversely proportional to the resistance in the circuit provided the voltage is constant. When the resistance is high, current is low, and vice-versa.</span>
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(i) a force of 35.0 n is required to start a 6.0-kg box moving across a horizontal concrete floor, (a) what is the coefficient o
Serjik [45]

a. The force applied would be equal to the frictional force.

F = us Fn

where, F = applied force = 35 N, us = coeff of static friction, Fn = normal force = weight

 

35 N = us * (6 kg * 9.81 m/s^2)

us = 0.595

 

b. The force applied would now be the sum of the frictional force and force due to acceleration

F = uk Fn + m a

where, uk = coeff of kinetic friction

 

35 N = uk * (6 kg * 9.81 m/s^2) + (6kg * 0.60 m/s^2)

uk = 0.533

4 0
3 years ago
What is the oldest tree and where?
Sphinxa [80]
Bristlecone pine<span>Until 2013, the oldest individual tree in the world was Methuselah, a 4,845-year-old Great Basin bristlecone pine (Pinus longaeva) in the White Mountains of California</span>
5 0
3 years ago
Read 2 more answers
A 350 gram mass is tied to a string and spin in a horizontal circle with a radius of 11.0cm.The speed of the mass is held consta
SSSSS [86.1K]

Explanation:

a) The angular speed omega is given defined as

omega = #rev/period = 1 rev/(0.6 s) = 1.7 rev/s

= (1.7 rev/s)×(2pi/rev) = 10.5 rad/s

b) v = (omega)×r

= (10.5 rad/s)(0.110 m)

= 1.16 m/s

7 0
3 years ago
Please help with this problem.
pochemuha

Answer:

its Y because the dot that represents it is close to S

6 0
4 years ago
Large electric fields in cell membranes cause ions to move through the cell wall. The field strength in a typical membrane is 1.
serg [7]

Explanation:

The given data is as follows.

          Electric field (E) = 1 \times 10^{7} N/C

          Charge (e) = 1.6 \times 10^{-19} C

Formula to calculate the magnitude of force is as follows.

                F = qE

                   = 1.6 \times 10^{-19} \times 1 \times 10^{7} N/C

                   = 1.6 \times 10^{-12} N

Therefore, we can conclude that magnitude of the force on a calcium ion with charge +e is  1.6 \times 10^{-12} N.

6 0
3 years ago
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