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Naily [24]
3 years ago
9

The measure of the force with which air molecules push on a surface is called

Physics
1 answer:
alex41 [277]3 years ago
7 0
It is called air pressure
You might be interested in
A loudspeaker in a parked car is producing sound whose frequency is 20 510 Hz. A healthy young person with normal hearing is sta
Vsevolod [243]

Answer:

The car must be moving away from the person.

Explanation:

From Doppler's Effect, we know that when a sound source moves towards a stationary observer, the apparent frequency of that sound increases. While the apparent frequency decreases if the source moves away from the stationary observer.

The audible range of frequencies for a human ear is 20 Hz to 20000 Hz. Therefore, in order for the sound of a loud speaker to be audible for the person, the frequency must decrease below 20000 Hz.

<u>Due to this reason, the car must be moving away from the person.</u>

4 0
3 years ago
A punter wants to kick a football so that the football has a total flight time of 4.70s and lands 56.0m away (measured along the
Sindrei [870]

Answer:

Explanation:

How long does the football need to rise?

4.70/3 = 2.35 s

What height will the football reach?

h = ½(9.81)2.35² = 27.1 m

With what speed does the punter need to kick the football?

vy = g•t = 9.81(2.35) = 23.1 m/s

vx = d/t = 56.0/4.70 = 11.9 m/s

v = √(vx²+vy²) = 26.0 m/s

At what angle (θ), with the horizontal, does the punter need to kick the football?

θ = arctan(vy/vx) = 62.7°

3 0
2 years ago
Blood in a carotid artery carrying blood to the head is moving at 0.15 m/s when it reaches a section where plaque has narrowed t
sp2606 [1]

Answer:

26.9 Pa

Explanation:

We can answer this question by using the continuity equation, which states that the volume flow rate of a fluid in a pipe must be constant; mathematically:

A_1 v_1 = A_2 v_2 (1)

where

A_1 is the cross-sectional area of the 1st section of the pipe

A_2 is the cross-sectional area of the 2nd section of the pipe

v_1 is the velocity of the 1st section of the pipe

v_2 is the velocity of the 2nd section of the pipe

In this problem we have:

v_1=0.15 m/s is the velocity of blood in the 1st section

The diameter of the 2nd section is 74% of that of the 1st section, so

d_2=0.74d_1

The cross-sectional area is proportional to the square of the diameter, so:

A_2=(0.74)^2 A_1=0.548 A_1

And solving eq.(1) for v2, we find the final velocity:

v_2=\frac{A_1 v_1}{A_2}=\frac{A_1 (0.15)}{0.548 A_1}=0.274 m/s

Now we can use Bernoulli's equation to find the pressure drop:

p_1 + \frac{1}{2}\rho v_1^2 = p_2 + \frac{1}{2}\rho v_2^2

where

\rho=1025 kg/m^3 is the blood density

p_1,p_2 are the initial and final pressure

So the pressure drop is:

p_1 - p_2 = \frac{1}{2}\rho (v_2^2-v_1^2)=\frac{1}{2}(1025)(0.274^2-0.15^2)=26.9 Pa

8 0
3 years ago
If the pressure of gas is doubled and its absolute temperature is quadrupled, the volume is what factor times the original?
Lapatulllka [165]

Answer:

Volume will increase by factor 2

So option (A) will be correct answer  

Explanation:

Let initially the volume is V pressure is P and temperature is T

According to ideal gas equation PV=nRT, here n is number of moles and R is gas constant

So V=\frac{nRT}{P}....................eqn 1

Now pressure is doubled and temperature is quadrupled

So new volume V_{new}=\frac{nR4T}{2P}=\frac{2nRT}{P} ........eqn 2

Now comparing eqn 1 nad eqn 2

V_{new}=2V

So volume will increase by factor 2

So option (A) will be correct answer

8 0
2 years ago
N the reactants of the general form of the single replacement reaction, the 'B' represents a _________ cation.
IrinaVladis [17]

1. Metallic

2. A, B

3. Unreactive

these are all right.

7 0
3 years ago
Read 2 more answers
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