Answer:
t = 460.52 min
Step-by-step explanation:
Here is the complete question
Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.
Solution
Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.
inflow = 0 (since the incoming water contains no dye)
outflow = concentration × rate of water inflow
Concentration = Quantity/volume = Q/200
outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.
So, Q' = inflow - outflow = 0 - Q/100
Q' = -Q/100 This is our differential equation. We solve it as follows
Q'/Q = -1/100
∫Q'/Q = ∫-1/100
㏑Q = -t/100 + c

when t = 0, Q = 200 L × 1 g/L = 200 g

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

㏑0.01 = -t/100
t = -100㏑0.01
t = 460.52 min
Answer:
one point (on origin),
Step-by-step explanation:
graph of Y=X^2 is parabolic ,and x intecept means the point where ,Y COORDINATE (ORDINATE) becomes 0
so now after putting y=0 in eqution we got
x^2=0
i.e, x=0
that means at (0,0) ,so only one point!
✌️:)
14 hours . Just divide 35 into 490 & ypu get 14
Answer:
Step-by-step explanation:
Givens
r = 14 miles / hour
Problem
Convert to feet per second.
Solution
Later on, you will learn how to solve these kinds of conversion problems using a method called Unit Analysis. Since you likely have not been taught this method, will just use proportions.
1 mile = 5280 feet
14 miles = x Cross multiply
x = 14 * 5280 Simplify
x = 73920 feet
1 hour = 3600 seconds
Answer
r = 73920 feet / 3600 seconds
r = 20.533 feet / secpmd
Answer:

Step-by-step explanation:
The question is to find the equation of the line going through the points (3,-1) and has a slope of -1.
First, the equation of a line is given as:
Equation = y = mx + b
Where
m is the slope
b is the y-intercept (y-axis cutting point)
We know the slope, so the equation becomes:
y = mx + b
y = -1x + b
y = -x + b
Now the point given is in the form (x,y), so
x = 3
y = -1
We substitute and find b:
y = -x + b
-1 = -3 + b
-1 + 3 = b
b = 2
Final Equation:
y = -x + 2