Answer:
vertex: (-1,25)
aos; -1
left x int: -6
right x int: 4
(not sure)
range is less than of equal to 25
Answer:
D
Step-by-step explanation:
Replace R1 with 1 and R3 with 0 you have -2(1)+0 which equals 0 and that matches matrix II. Repeat the process with the other numbers in R1 and R3 and they all come out equal therefor the answer is D.
Answer:
Do no reject null hypothesis.
Conclusion:
there is no sufficient statistical evidence at 0.025 level of significance to support the claim.
Step-by-step explanation:
Given that;
mean x" = 5.4
standard deviation σ = 0.7
n = 6
Null hypothesis H₀ : μ = 5.0
Alternative hypothesis H₁ : μ > 5.0
∝ = 0.025
now,
t = ( 5.4 - 5.0) / ( 0.7/√6) = 0.4 / 0.2857 = 1.4
degree of freedom df = n-1 = 6 - 1 = 5
T critical = 2.571
Therefore; t < T critical,
Do no reject null hypothesis.
Conclusion:
there is no sufficient statistical evidence at 0.025 level of significance to support the claim.
Basically what you do is (the ^ arrow meaning exponent)
You take 3.7 + 4.45 x 10^20
Then 8.15 x 10^20, remove the decimal of 8.15 = 815 x 10^-2 x 10^20
815 x 10^18 = <span>815000000000000000000</span>
Answer:
27,29,38,39,42,52,53
Step-by-step explanation:
