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Juli2301 [7.4K]
3 years ago
5

If the graph of the function f is defined by:

Mathematics
1 answer:
hoa [83]3 years ago
7 0
G(x) =x^2+4
This is because the last number (+4) represents the y intercept, so lowering the number by fore would lower the whole function by four.
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Which of the following is the graph of the quadratic function? y=x^2+4-12
tiny-mole [99]

Answer:

Graph B

Step-by-step explanation:

The solutions to a quadratic equation are the points on which we have the graph of the curve touching the x-axis

Now the first thing we will do here is to solve the quadratic equation graph;

x^2 + 4x -12 = 0

x^2 +6x - 2x -12 = 0

x (x + 6) -2(x + 6) = 0

(x-2)(x + 6) = 0

x = 2 or -6

So the graph that touches the x-axis at the points x = 2 and x = -6 is the solution to the quadratic equation

Graph B is the closest to what we have as answer

5 0
4 years ago
What is the midpoint of the segment shown below?
alex41 [277]

Answer:

B. (-9/2, -11/2)

Step-by-step explanation:

-12+3 / 2 = -9/2

-3+-8 / 2 = -11/2

6 0
3 years ago
PLEASE HELP ME WITH 32D
mr_godi [17]

Answer:

Help me please in my question

4 0
3 years ago
I NEED HELP ON THIS WHOLE PAGE MAKE SURE YOUR ANSWER MAKES SENSE
Otrada [13]
1: 5,800

2: 112.5 (total weight, divide by 2, subtract 17 lb)

5: .8 (4 divided by 5)

6: \frac{66}{100}

7: 1,728

9: 9 inches

10: 1.2

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5 0
3 years ago
A customer can pay GH➣900.00 per month on a mortgage payment.
nadezda [96]

Answer:

  $74,748.11

Step-by-step explanation:

In order to make use of the amortization formula, we need to find the equivalent monthly interest rate.

When 12% interest is compounded continuously, the annual multiplier is ...

  e^0.12 ≈ 1.127497

The equivalent multiplier when the interest is compounded monthly is the 12th root of this,

  (e^0.12)^(1/12) = e^0.01 ≈ 1.0100502 = 1 + r

___

The amortization formula tells us that monthly payment amount A will pay off principal P in n months:

  P = A(1 -(1 +r)^-n)/r = $900(1 -1.0100502^-180)/0.0100502

  P = $74,748.11

The customer can pay off a 12% loan of $74,748.11 at the rate of $900 per month for 15 years.

5 0
3 years ago
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