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user100 [1]
3 years ago
13

The point-slope form of a line that has a slope of –2 and passes through point (5, –2) is shown below.

Mathematics
2 answers:
gladu [14]3 years ago
5 0

Answer:

y=-2x+8

Step-by-step explanation:

Leviafan [203]3 years ago
3 0

Answer:

  y = -2x +8

Step-by-step explanation:

One way to write the equation of a line with slope m through point (h, k) in point-slope form is ...

  y = m(x -h) +k

In this form, the equation of the line is ...

  y = -2(x -5) -2

Eliminating parentheses and collecting terms puts this in slope-intercept form:

  y = -2x +8

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Find the coordinates of the missing endpoint if m is the midpoint of ab. a(-9, -4) and m(-7, -2.5)
Julli [10]

Answer:

The coordinates of the point b are:

b(x₂, y₂)  = (-5, -1)

Step-by-step explanation:

Given

As m is the midpoint, so

m(x, y) = m (-7, -2.5)

The other point a is given by

a(x₁, y₁) = a(-9, -4)

To determine

We need to determine the coordinates of the point b

= ?

Using the midpoint formula

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

substituting (x, y) = (-7, -2.5), (x₁, y₁) = (-9, -4)

\left(-7,\:-2.5\right)=\left(\frac{x_2+\left(-9\right)}{2},\:\:\frac{y_2+\left(-4\right)}{2}\right)

Thus equvating,

Determining the x-coordinate of b

[x₂ + (-9)] / 2 = -7

x₂ + (-9) = -14

x₂ - 9 = -14

adding 9 to both sides

x₂ - 9 + 9 = -14 + 9

x₂ = -5

Determining the y-coordinate of b

[y₂ + (-4)] / 2 = -2.5

y₂ + (-4) = -2.5(2)

y₂ - 4 = -5

adding 4 to both sides

y₂ - 4 + 4 = -5 + 4

y₂ = -1

Therefore, the coordinates of the point b are:

b(x₂, y₂)  = (-5, -1)

6 0
3 years ago
Can someone PLEASE help me with Trigonometry???
Svetach [21]
\bf sin^2(2\theta)-7sin(2\theta)-1=0\\\\
-------------------------------\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{49-4(1)(-1)}}{2(1)}\implies sin(2\theta)=\cfrac{7\pm\sqrt{49+4}}{2}
\\\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{53}}{2}\implies 2\theta=sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)
\\\\\\
\theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}

but anyway, the numerator will give the angles, and θ is just half of each

\bf \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}\\\\
-------------------------------\\\\
sin^{-1}\left( \frac{7+\sqrt{53}}{2} \right)\implies sin^{-1}(7.14)\impliedby \textit{greater than 1, no good}
\\\\\\
sin^{-1}\left( \frac{7-\sqrt{53}}{2} \right)\implies sin^{-1}(-0.14) \approx -8.05^o
\\\\\\
\theta=\cfrac{-8.05}{2}\implies \theta=-4.025

ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025

so the angle is 355.975°

now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°

and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there
7 0
4 years ago
..........................answer
Akimi4 [234]

Well it’s simply the answer

8 0
3 years ago
Read 2 more answers
A lunch menu has 4 different sandwiches, 2 different soups, and 5 different drinks. How many different lunches consisting of a s
oksian1 [2.3K]
To find out all of the possible combinations, just multiply the amount of each variable:

4*2*5 = 40

There are 40 different combinations consisting of a sandwich, soup, and drink.
5 0
4 years ago
Given circle O. Find all the missing values
Norma-Jean [14]

Step-by-step explanation:

Do you still need the answer to this?

3 0
3 years ago
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