The correct question is
<span>What are the vertex and x-intercepts of the graph of the function given below?
y = x</span>²<span>-2x-35
step 1
convert the equation in the vertex form
y+35=x</span>²-2x
y+35=(x²-2x+1-1)
y+35+1=(x²-2x+1)
y+36=(x-1)²------> equation in the vertex form
the vertex is the point (1,-36)
the answer Part a) is
the vertex is the point (1,-36)
Part b) Find the x-intercepts
we know that
the x-intercepts is when y=0
so
y+36=(x-1)²
for y=0
(x-1)²=36
(+/-)(x-1)=√36-------> (+/-)(x-1)=6
(+)(x-1)=6------> x=6+1-----> x=7
(-)(x-1)=6-----> x=1-6-----> x=-5
the x-intercepts are the points
(7,0) and (-5,0)
the answer part b) is
the x-intercepts are the points (7,0) and (-5,0)
the total answer is the option
<span>A. Vertex: (1, -36); x-intercepts: (7, 0) and (-5, 0)</span>
Answer:
800 is the answer
Step-by-step explanation:
90-40= 50---->4000/50=800
Answer:
Step-by-step explanation:
Find the equation of the segment going from (0,-5) to (3,7)
y intercept = -5
Slope = (-5 - 7) / (0 - 3) = -12/-3 = 4
equation: y = 4x - 5
g(x) = x^2 / f(x)
f(x)= (4x - 5)
g(x) = x^2 / (4x - 5)
g'(x) = x^2 * (4x - 5)^-1
g'(x) = 2x*(4x - 5)^-1 + (-1) *4* x^2 (4x - 5)^-2
I will leave that monster the way it is and just find g'(1)
g'(1) = 2(1) * (4(1) - 5)^-1 + (-1) (1)^2 *4* (4(1) - 5)^-2
g'(1) = 2(1) * (-1)^-1 + (-1) (1)^2 *4 * (-1)^2
g'(1) = -2 + (-1) (1)^2 (4)
g'(1) = - 2 + (-1) (1)^2 (4)
g'(1) = - 2 - 4
g'(1) = - 6
Answer:
A. 50.24
Step-by-step explanation:
f(4) = 3.14 times 4²
f(4) = 3.14(16)
f(4) = 50.24
<h2><u><em>xoxo, </em></u></h2><h2><u><em>your highness...</em></u></h2>
