Can someone please help im struggling

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

5 0

Answer:

81 units³

Step-by-step explanation:

V = Length x Widht x Height

= 9 x 3 x 3

= 81 units³

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The function f(x)=600+2x over x yields the average cost in dollars for a company to produce x calendars. Which statement best fi

nevsk [136]

Answer:

The correct option is a.

Step-by-step explanation:

The average cost function is

$f(x)=\frac{600+2x}{x}$

Where x is the number of calendars produced.

The average cost formula is

$AC=\frac{\text{Total Cost}}{\text{Number of items}}$

Therefore the total cost is defined b the function

$g(x)=600+2x$

Here 600 is the initial cost and the cost each unit is 2.

Initial cost is the fixed cost which occurs at zero level of productivity.

The company spends $600 on a new computer and printer before beginning the project. The option (a) is correct.

8 0

3 years ago

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Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360

Natasha2012 [34]

$\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]$

$\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]$