Answer:
D = L/k
Step-by-step explanation:
Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is
dA/dt = in flow - out flow
Since litter falls at a constant rate of L grams per square meter per year, in flow = L
Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow
So,
dA/dt = in flow - out flow
dA/dt = L - Ak
Separating the variables, we have
dA/(L - Ak) = dt
Integrating, we have
∫-kdA/-k(L - Ak) = ∫dt
1/k∫-kdA/(L - Ak) = ∫dt
1/k㏑(L - Ak) = t + C
㏑(L - Ak) = kt + kC
㏑(L - Ak) = kt + C' (C' = kC)
taking exponents of both sides, we have

When t = 0, A(0) = 0 (since the forest floor is initially clear)


So, D = R - A =

when t = 0(at initial time), the initial value of D =

Answer:
sin(<A)
Step-by-step explanation:
The answer would be C, 15
They way I would do it other than with a calculator would be
27 x (90 - 0.5) which is the same as 27 x 89.5
=> 27 x 90 - 27 x 0.5
27 x 90 is (3 x 9) x 90 or 3 x 9 x 90
9 x 90 = 810
3 x 810 = 2430
Then subtract 27 x 0.5, or 27 / 2
2430 - 27 / 2
=> 2430 - 13.5
= 2416.5
Final answer:
2416.5
Hope I helped :)
Answer:
7
Step-by-step explanation: