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Maksim231197 [3]
3 years ago
9

Please help me now I need help

Mathematics
1 answer:
Fudgin [204]3 years ago
4 0

Answer: B

Step-by-step explanation:

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The perimeter of a rectangle,p, is given by p =2L + 2W , where L is its length and w is its width what is the perimeter of a rec
ryzh [129]

Answer:

60ft

Step-by-step explanation:

        multiple the length by 2

15 times two equals 30

       multiple the width by two

15 times two equals 30

       add the total lengths and widths

30 plus 30 equals 60

ans=60

6 0
3 years ago
Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.
mart [117]

Answer:

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

Step-by-step explanation:

The given expression is  

\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}    [\because a^ma^n=a^{m+n}]

\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}

\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}         [\because a^{-n}=\dfrac{1}{a^n}]

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

5 0
4 years ago
How many thousands are in 5,000 ones
Iteru [2.4K]
5 thousands in 5,000 ones.
3 0
4 years ago
Read 2 more answers
Andrew's bowling scores are approximately normally distributed with mean 130 and standard deviation 21, while Pam's scores are n
White raven [17]

Answer:

2

Step-by-step explanation:

7 0
3 years ago
JKLM is a rhombus. KM is 10 and JL is 24. Find the perimeter of the rhombus.
Ahat [919]
Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units

5 0
3 years ago
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