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3 years ago

What is the output of the function f(p) = 3p – 2 when the input is 2? A. 0 B. 2 C. 4 D. 6 E. 8

Mathematics

2 answers:

bazaltina [42]3 years ago

8 0

Step-by-step explanation:

Step 1: Find f(2)

$f(p) = 3p - 2$

$f(2) = 3(2) - 2$

$f(2) = 6 - 2$

$f(2) = 4$

Answer: Option C, 4

EastWind [94]3 years ago

4 0

Answer:

C. 4

Step-by-step explanation:

f(p) = 3p - 2

Is a function with:

Input: p

Output: 3p - 2

p = 2

f(2) = 3(2) - 2 = 6 - 2 = 4

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Find the slope of the line ? plz and thank you

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3 years ago

What is the y- intercept of a line that goes through the points (3,-2)& has a slope of -4?

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Answer:

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Step-by-step explanation:

this is the equation of a straight line that is generally written

y = m × x + q

m is the slope of the line and is the proportionality coefficient between y and x.

The larger m is, the more the line is hanging

q (-3) is the intercept with the Y axis and is the value you find if you put x=0 (this is the axis y equation)

similarly if you put Y=0 (that is the equation of X axis you find the intercept with X axis that is X= 3/2

graph{2x-3 [-10, 10, -5, 5]}

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3 years ago

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2 years ago

In a widget factory, machines A, B, and C manufacture, respectively, 20, 30, and 50 percent of the total. Of their output 6, 3,

steposvetlana [31]

Answer:

38.71% probability it was manufactured by machine A.

29.03% probability it was manufactured by machine B.

32.26% probability it was manufactured by machine C.

Step-by-step explanation:

We have these following probabilities:

A 20% probability that the chip was fabricated by machine A.

A 30% probability that the chip was fabricated by machine B.

A 50% probability that the chip was fabricated by machine C.

A 6% probability that a chip fabricated by machine A was defective.

A 3% probability that a chip fabricated by machine B was defective.

A 2% probability that a chip fabricated by machine C was defective.

The question can be formulated as:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

What are the probabilities that it was manufactured by machines A, B, and C?

Machine A

What is the probability that the widget was manufactures by machine A, given that it is defective?

P(B) is the probability that it was manufactures by machine A. So $P(B) = 0.20$

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine A. So $P(A/B) = 0.06$

P(A) is the probability that a widget is defective. This is the sum of 6% of 20%, 3% of 30% and 2% of 50%. So

$P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.2*0.06}{0.031} = 0.3871$

38.71% probability it was manufactured by machine A.

Machine B

What is the probability that the widget was manufactures by machine B, given that it is defective?

P(B) is the probability that it was manufactures by machine B. So $P(B) = 0.30$

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine B. So $P(A/B) = 0.03$

$P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.03}{0.031} = 0.2903$

29.03% probability it was manufactured by machine B.

Machine C

What is the probability that the widget was manufactures by machine C, given that it is defective?

P(B) is the probability that it was manufactures by machine C. So $P(B) = 0.50$

P(A/B) is the probability that a widget is defective, given that it is manufactured by machine C. So $P(A/B) = 0.02$

$P(A) = 0.06*0.20 + 0.03*0.30 + 0.02*0.5 = 0.031$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.02}{0.031} = 0.3226$

32.26% probability it was manufactured by machine C.

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