Answer:
HBr(aq) + LiOH(aq) → LiBr(aq) + H2O(l)
Explanation:
A neutralization reaction is a process in which an acid, aqeous HBr reacts completely with an appropriate amount of base, aqueous LiOH to produce salt, aqueous LiBr and water, liquid H2O only.
HBr(aq) + LiOH(aq) → LiBr(aq) + H2O(l)
Acid + base → Salt + Water.
During this reaction, the hydrogen ion, H+, from the HBr is neutralized by the hydroxide ion, OH-, from the LiOH to form the water molecule, H2O.
Thus, it is called a neutralization reaction.
Answer:
V KOH = 41 mL
Explanation:
for neutralization:
- ( V×<em>C </em>)acid = ( V×<em>C </em>)base
∴ <em>C </em>H2SO4 = 0.0050 M = 0.0050 mol/L
∴ V H2SO4 = 41 mL = 0.041 L
∴ <em>C</em> KOH = 0.0050 N = 0.0050 eq-g/L
∴ E KOH = 1 eq-g/mol
⇒ <em>C</em> KOH = (0.0050 eq-g/L)×(mol KOH/1 eq-g) = 0.0050 mol/L
⇒ V KOH = ( V×<em>C </em>) acid / <em>C </em>KOH
⇒ V KOH = (0.041 L)(0.0050 mol/L) / (0.0050 mol/L)
⇒ V KOH = 0.041 L
NaClO, K2CO3, and NaF will form basic soltions.
Answer is: the osmotic pressure of aqueous solution of aspirin is 0.0407 atm.
m(C₉H₈O₄) = 75 mg ÷ 1000 mg/g = 0.075 g.
n(C₉H₈O₄) = 0.075 g ÷ 180.16 g/mol.
n(C₉H₈O₄) = 0.000416 mol.
c(C₉H₈O₄) = 0.000416 mol ÷ 0.250 L.
c(C₉H₈O₄) = 0.00167 M; concentration of solution.
T(C₉H₈O₄) = 25°C = 298.15 K; temperature in Kelvins.
R = 0.08206 L•atm/mol•K; universal gas constant.
π = c(C₉H₈O₄) • T(C₉H₈O₄) • R.
π = 0.00167 mol/L • 298.15 K • 0.08206 L•atm/mol•K.
π = 0.0407 atm.
