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Over [174]
3 years ago
5

In the bromination of arenes, which of the following statements regarding the reaction is true?a.The hydrocarbon is used in exce

ss.spaceb.Equimolar quantities of bromine and the hydrocarbon are used.spacec.Bromine is used in excess.spaced.Stoichiometry does not matter in this experiment since we are only interested in the rate of the reaction.
Chemistry
1 answer:
Olenka [21]3 years ago
8 0

The hydrocarbon is used in excess.

<h3><u>Explanation</u>:</h3>

The bromination of an arene is not simple as bromination of an alkane. This is because the carbocation or free radicle formation in benzene is a very energy consuming process. This is why a lewis base like aluminium bromide or ferric bromide is used. The ferric bromide takes in the bromine radicle and forms the brominium cation which helps in the formation of electrophile. Now this electrophile brominium cation attacks the benzene ring and forms a temporary sp3 hybrid carbon intermediate. Then the hydrogen is taken by the FeBr4- forming HBr and regenerating the FeBr3 as well as Aromaticity of the arene species at the same time. Here hydrocarbon is used in excess just to prevent the chances of multiple substitution in the same arene molecule.

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A researcher wants to test the solubility (property of being dissolved) of salt in water as the temperature of the water increas
Leya [2.2K]
The researcher may first weight the beaker with water and then start to heat the water to a constant temperature, for example 30 °C and then start adding salt and stirring. He should add salt slowly until solid salt starts to become visible and the solution starts becoming cloudy. When this happens, he should quickly weigh the beaker. The increase in mass is the mass of salt dissolved at that temperature.
The procedure is then repeated but at an increased temperature until 5-6 temperatures have been tested.
3 0
3 years ago
List the number of each type of atom on the left side of the equation 2C10H22(l)+31O2(g)→20CO2(g)+22H2O(g)
Leokris [45]

<u>Answer:</u>

<em>20, 44, 62 </em>

<em></em>

<u>Explanation:</u>

To find the number of atoms of each element, we multiply coefficient and subscript  

For example 5 Ca_1 Cl_2 contains  

5 × 1 = 5 ,Ca atoms and

5 × 2 = 10, Cl atoms  

If there is a bracket in the chemical formula  

For example 3Ca_3 (P_1 O_4 )_2

we multiply coefficient × subscript × number outside the bracket to find the number of atoms  

(Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So

3 × 3 = 9 , Ca atoms  

3 × 1 × 2 = 6, P atoms  

3 × 4 × 2 = 24, O atoms are present.

So let us find the number of atoms of each element on the left  side of the equation  

2C_{10} H_{22} (l)+31O_2 (g)\Rightarrow 20CO_2 (g)+22H_2 O(g)

Number of C atoms = 2 × 10 = 20

Number of H atoms = 2 × 22 = 44

Number of O atoms = 31 × 2 = 62

20, 44, 62  are the Answers.

3 0
3 years ago
Which answer best describes what is happening in the following reaction?
NISA [10]

A.  This is not a redox reaction. It is an example of combustion.

<h3>Combustion reaction of hydrocarbon</h3>

During the combustion of a hydrocarbon, the hydrocarbon reacts with oxygen to create carbon dioxide, water, and heat.

<h3>Example of combustion reaction</h3>

2C8H18 + 25O2 → 16CO2 + 18H2O

Thus, we can conclude that, this is not a redox reaction. It is an example of combustion.

Learn more about combustion here: brainly.com/question/9425444

#SPJ1

8 0
1 year ago
How many hydrogen atoms are needed to form five water molecules
BARSIC [14]
2 Hydrogen Atoms Are Needed To Form Five Water Molecules
8 0
3 years ago
Read 2 more answers
In a mixture of 2 ideal gases, A and B, PA = 0.2PB, what is the mole fraction of A?
Alborosie

Answer:

0.1667

Explanation:

Hello,

Dalton's law defines:

y_i=\frac{P_i}{P_T}

A total pressure is:

P_T=P_A+P_B

So, for A (solving for P_A in the previous equation, we get:

y_A=\frac{P_A}{P_A+P_B}

Since P_A=0.2P_B, we obtain:

y_A=\frac{P_A}{P_A+P_A/0.2}\\y_A=\frac{1}{6}\\y_A=0.1667}

Best regards.

7 0
3 years ago
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