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Nataliya [291]
3 years ago
12

ATOMS , help me solve this , and thx for your help

Chemistry
2 answers:
Ganezh [65]3 years ago
6 0
I think is 8 try it but I’m not 100% sure
lys-0071 [83]3 years ago
4 0

Answer:

8?

im not sure

Explanation:

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5. By approximately what factor would the mass of a sample of copper-66
Fed [463]
That’s picture right there should help u with your works

7 0
3 years ago
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A 0.600 g sample of diprotic acid H2X is dissolved in water, and titrated to the equivalence point with 40.0 mL of 0.200 M NaOH.
9966 [12]

Answer:

150 g/mol

Explanation:

Let's consider the complete neutralization of a diprotic acid H₂X with NaOH.

H₂X + 2 NaOH → Na₂X + 2 H₂O

40.0 mL of 0.200 M NaOH. were required to reach the endpoint. The reacting moles of NaOH are:

0.0400 L × 0.200 mol/L = 8.00 × 10⁻³ mol

The molar ratio of H₂X to NaOH is 1:2. The reacting moles of H₂X are 1/2 × 8.00 × 10⁻³ mol = 4.00 × 10⁻³ mol.

4.00 × 10⁻³ moles of H₂X have a mass of 0.600 g. The molar mass of H₂X is:

0.600 g/4.00 × 10⁻³ mol = 150 g/mol

8 0
3 years ago
Which of the following is an example of a physical change?
dangina [55]
D it is only physical and not chemical
5 0
3 years ago
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How many grams of CuSO4 • 5H2O do you need to make 0.8 L of a 0.6 M solution
Bumek [7]
<h3><u>Unders</u><u>tanding</u><u> </u><u>the</u><u> </u><u>conc</u><u>ept</u><u>:</u><u>-</u></h3>

Here the concept of Molarity used .We will put the formula of Molarity then we find moles of copper sulphate .Then we can find the.Given weight of Copper sulphate.So let's do

<h3>Solution:-</h3>

  • Volume of Solvent=0.8L
  • Molarity=0.6M

We know

\boxed{\sf Molarity=\dfrac{Moles\:of\: solute}{Volume\:of\: Solvent \:in\;L}}

\\ \rm\longmapsto Moles\:of\: solute=Molarity\times Volume\:of\: Solvent\:in\:L

\\ \rm\longmapsto Moles\:of\: Solute=0.8(0.6)

\\ \rm\longmapsto Moles\:of\: Solute=0.48mol

Now

Molar Mass of Solute:-

\\ \rm\longmapsto CuSO_4.5H_2O

\\ \rm\longmapsto 65u+32u+4(16u)+5(2\times 1u+16u)

\\ \rm\longmapsto 96u+64u+5(2+16)

\\ \rm\longmapsto 160u+90u

\\ \rm\longmapsto 250u

\\ \rm\longmapsto 250g/mol

Now

\boxed{\sf No\:of\:moles=\dfrac{Given\:Mass}{Molar\:Mass}}

\\ \rm\longmapsto Given\:Mass=No\:of\:Moles\times Molar\:Mass

\\ \rm\longmapsto Given\:Mass=250(0.48)

\\ \rm\longmapsto Given\:Mass=120g

8 0
3 years ago
Compounds can be separated by<br><br> chemical means<br> physical means<br> boiling<br> pressure
Gennadij [26K]
In order to compounds to be serparated, chemical means are needed. For example, if it you want to separate hydrogen and oxygen in the water ,an electric current should flow through it and that is a kind of chemical means(it is related to the chemical properties of the elements .)
While ,if there is a mixture ,it's components are rather separated easily in physical means. For instance, if you have a salt water, you are able to divide them by using each physical properties. Water is able to turn to a state of gas by evaporating or boiling. Using such properties, you could separate water from salt. Therefore, separating compounds and mixtures are all about the components physical or chemical properties.

So, the answer is a. I hope it will help you^^
6 0
3 years ago
Read 2 more answers
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