This is a calorimetry question so a few things you will need for this. The calorimetry equation q=mcΔT & the specific heat of water (4.2J/g•°C). Other definitions are:
q = heat added/released by a sample
m = mass of sample
c=specific heat of sample
ΔT = change in temperature
from here we can rearrange the equation to state:
q/(mc) = ΔT
1200J/((20.0g)(4.2J/g•°C)) = ΔT
14°C = ΔT
If the starting temperature was 95.0°C and we know that the temperature was cooled by 14°C then the final temperature of the water would be 81.
Group 6 elements like Oxygen like to take on the extra two electrons to become a 2- anion and take on the noble gas configuration. so the O^2-, which looks like O=O, will have two oxygens sharing two electrons.... answer is O^2-
Scientists often communicate their research results in three general ways. but this only asks for 2 so I'm giving 2 haah anyway .One is to publish their results in peer reviewed journals that can be ready by other scientists. Two is to present their results at national and international conferences where other scientists can listen to there presentations or presentations in general.
