Perform the following calculations and give your answer with the correct number of significant figures of 10.5+11.62

How does induced transmutation produce trans uranium elements ?

kifflom [539]

Answer: Artificial transmutation may occur in machinery that has enough energy to cause changes in the nuclear structure of the elements. This releases, on average, 3 neutrons and a large amount of energy. The released neutrons then cause fission of other uranium atoms, until all of the available uranium is exhausted.
Hope this helped!!
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5 0

3 years ago

Calculate the amount of oxygen gas collected by the displacement of water at 14◦C if the atmospheric pressure is 790 Torr and th

zhannawk [14.2K]

Answer : The amount of oxygen gas collected are, 0.217 mol

Explanation :

Using ideal gas equation :

$PV=nRT$

where,

P = pressure of gas = $(790-12)torr=778torr=1.02atm$ (1 atm = 760 torr)

V = volume of gas = 5 L

T = temperature of gas = $14^oC=273+14=287K$

n = number of moles of gas = ?

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

$(1.02atm)\times (5L)=n\times (0.0821L.atm/mol.K)\times (287K)$

$n=0.217mole$

Thus, the amount of oxygen gas collected are, 0.217 mol

8 0

4 years ago

Can anybody answer this question of chemistry?

maw [93]

Answer:

Answer:A

Answer:AExplanation:

Answer:AExplanation:Molar Mass of glucose = (6×12)+(1×12)+(16×6)= 180g/mol

= 180g/molNumber of moles of Glucose = Mass/Molar Mass

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556

= 180g/molNumber of moles of Glucose = Mass/Molar Mass= 5000/180= 27.7778molesIn the balanced equation of fermentation, the ratio of glucose to ethanol is 2:1Therefore the number of moles of ethanol is 2×27.7778=55.5556molesMass of ethanol= Molar Mass of ethanol × Number of moles={(12×2)+(1×6)+16} × 55.5556= 46.5×55.5556= 2555.55

4 0

3 years ago

Read 2 more answers

J.J. Thompson's experiments with cathode rays ended up ___

Nata [24]

I think it might be A or D, hope I helped! Sorry if I didn't!!

4 0

3 years ago

Read 2 more answers

. What is the molarity of a solution that was prepared by dissolving 80.0 g of CaCl2 (molar mass = 111.1 g/mol) in enough water

garri49 [273]

Explanation:

Molarity = mol/L or g/L

Data:

Mass>80.0g

Mr of CaCl2>111.1g/mol

V>500mL

Convert mL to Litres;. mole=g/Mr

1L=1000mL. =80g/111.1g/mol

x=500mL. =0.720072007mol

x=0.5L

Molarity= mole/volume

=0.720072007mol/0.5L

=1.440144014mol/L

=1.4401mol/L

Hope this helps. Depending on the question you can also find it in g/L but mol/L is safer.

7 0

3 years ago