What is the correct orbital diagram for carbon

Which term describes a section of Earht's structure below moving continents as parts of large plates?

Snezhnost [94]

"Asthenosphere" describes a section of Earth's structure below moving continents as parts of large plates.

Answer: Option C

Explanation:

The asthenosphere denoted as the upper mantle of a very sticky, mechanically weak and flexible area in the earth. It is located below the surface of the lithosphere at depths of about 80 and 200 km (in terms of miles, 50 and 120). The boundary is commonly called the lithospheric LAB - asthenosphere.

The asthenosphere is nearly solid, though some of its regions could be molten below mid-ocean ridges for an instance. The lower asthenosphere boundary isn't well defined. The asthenosphere's thickness depends primarily on the temperature.

8 0

3 years ago

an element has a metallic gray appearance. it also has the properties of both a metal and a nonmetal. in which section of the pe

irinina [24]

If it has properties of metal and non metal it is considered a metalloid there are very few spots in which metalloids are located the spots I circled on a blank periodic tables are where the metalloids are located on an actual periodic table your only options are
boron(B) silicon(si) germanium(Ge) arsenic(As)antimony(Sb)tellurium(Te)astatine(At)those are the only places on the periodic table that has metalloids... I hope this helps

6 0

2 years ago

Which object in the solar system is shown in the image? (15 points)

valentinak56 [21]

Answer:

its an asteroid

and it seems to be same as picture and what I knew

have a great time

6 0

2 years ago

What is the total gas pressure in a sealed flask that contains oxygen at a partial pressure of 0.35 atm and water vapor at a par

Fofino [41]

According to Dalton's Law, in a mixture of non-reacting gasses, thetotal pressure exerted is the sum of the partial pressures of the component gasses. In more complicated circumstances, equilibrium states come into effect, but fortunately for us, oxygen is non-reactive with water vapor.

5 0

3 years ago

The heats of combustion of ethane (C2H6) and butane (C4H10) are 52 kJ/g and 49 kJ/g, respectively. We need to produce 1.000 x 10

LekaFEV [45]

Answer :

(1) The number of grams needed of each fuel $(C_2H_6)\text{ and }(C_4H_{10})$ are 19.23 g and 20.41 g respectively.

(2) The number of moles of each fuel $(C_2H_6)\text{ and }(C_4H_{10})$ are 0.641 moles and 0.352 moles respectively.

(3) The balanced chemical equation for the combustion of the fuels.

$C_2H_6+\frac{7}{2}O_2\rightarrow 2CO_2+3H_2O$

$C_4H_{10}+\frac{13}{2}O_2\rightarrow 4CO_2+5H_2O$

(4) The number of moles of $CO_2$ produced by burning each fuel is 1.28 mole and 1.41 mole respectively.

The fuel that emitting least amount of $CO_2$ is $C_2H_6$

Explanation :

Part 1 :

First we have to calculate the number of grams needed of each fuel $(C_2H_6)\text{ and }(C_4H_{10})$ .

As, 52 kJ energy required amount of $C_2H_6$ = 1 g

So, 1000 kJ energy required amount of $C_2H_6$ = $\frac{1000}{52}=19.23g$

and,

As, 49 kJ energy required amount of $C_4H_{10}$ = 1 g

So, 1000 kJ energy required amount of $C_4H_{10}$ = $\frac{1000}{49}=20.41g$

Part 2 :

Now we have to calculate the number of moles of each fuel $(C_2H_6)\text{ and }(C_4H_{10})$ .

Molar mass of $C_2H_6$ = 30 g/mole

Molar mass of $C_4H_{10}$ = 58 g/mole

$\text{ Moles of }C_2H_6=\frac{\text{ Mass of }C_2H_6}{\text{ Molar mass of }C_2H_6}=\frac{19.23g}{30g/mole}=0.641moles$

and,

$\text{ Moles of }C_4H_{10}=\frac{\text{ Mass of }C_4H_{10}}{\text{ Molar mass of }C_4H_{10}}=\frac{20.41g}{58g/mole}=0.352moles$

Part 3 :

Now we have to write down the balanced chemical equation for the combustion of the fuels.

The balanced chemical reaction for combustion of $C_2H_6$ is:

$C_2H_6+\frac{7}{2}O_2\rightarrow 2CO_2+3H_2O$

and,

The balanced chemical reaction for combustion of $C_4H_{10}$ is:

$C_4H_{10}+\frac{13}{2}O_2\rightarrow 4CO_2+5H_2O$

Part 4 :

Now we have to calculate the number of moles of $CO_2$ produced by burning each fuel to produce 1000 kJ.

$C_2H_6+\frac{7}{2}O_2\rightarrow 2CO_2+3H_2O$

From this we conclude that,

As, 1 mole of $C_2H_6$ react to produce 2 moles of $CO_2$

As, 0.641 mole of $C_2H_6$ react to produce $0.641\times 2=1.28$ moles of $CO_2$

and,

$C_4H_{10}+\frac{13}{2}O_2\rightarrow 4CO_2+5H_2O$

From this we conclude that,

As, 1 mole of $C_4H_{10}$ react to produce 4 moles of $CO_2$

As, 0.352 mole of $C_4H_{10}$ react to produce $0.352\times 4=1.41$ moles of $CO_2$

So, the fuel that emitting least amount of $CO_2$ is $C_2H_6$

5 0

3 years ago