100+7=107
107% of 45.09=1.07 times 45.09=48.2463
round to nearest cent
$48.25 is the top price
Answer:
![\displaystyle 4\sqrt[7]{x^3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%204%5Csqrt%5B7%5D%7Bx%5E3%7D)
General Formulas and Concepts:
<u>Algebra I</u>
- Exponential Rule [Root Rewrite]:
![\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%5Bn%5D%7Bx%7D%20%3D%20x%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<em />
<em />
<em />
<u>Step 2: Rewrite</u>
- Split:

- Rewrite [Exponential Rule - Root Rewrite]:
![\displaystyle 4\sqrt[7]{x^3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%204%5Csqrt%5B7%5D%7Bx%5E3%7D)
He bought 200 of them
200*2.80=$560
marked up 90%
90% of 560=0.9*560=504
560+504=1064
he sold all 200 for a total of 1064, or an average price of $5.32 each
Not sure if you mean to ask for the first order partial derivatives, one wrt x and the other wrt y, or the second order partial derivative, first wrt x then wrt y. I'll assume the former.


Or, if you actually did want the second order derivative,
![\dfrac{\partial^2}{\partial y\partial x}(2x+3y)^{10}=\dfrac\partial{\partial y}\left[20(2x+3y)^9\right]=180(2x+3y)^8\times3=540(2x+3y)^8](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpartial%5E2%7D%7B%5Cpartial%20y%5Cpartial%20x%7D%282x%2B3y%29%5E%7B10%7D%3D%5Cdfrac%5Cpartial%7B%5Cpartial%20y%7D%5Cleft%5B20%282x%2B3y%29%5E9%5Cright%5D%3D180%282x%2B3y%29%5E8%5Ctimes3%3D540%282x%2B3y%29%5E8)
and in case you meant the other way around, no need to compute that, as

by Schwarz' theorem (the partial derivatives are guaranteed to be continuous because

is a polynomial).
Answer
25f + 100c <span>≤ 700
hope it helps</span>