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2 years ago

Two points located on are J(1,-4) and K(-2,8). What is the slope of ?

Mathematics

1 answer:

vodka [1.7K]2 years ago

3 0

Answer:

-4

Step-by-step explanation:

The slope is usually a function of the differences in y divided by the differences in x, and it can be described in the following equation,

$Slope = \frac{y_{1} - y_{2} }{x{1} - x{2}}$ (1)

We can select any of the two points to be our first point, let's say, J(1,-4) is point 1, so J (x1,y1). In other words, $x_1 = 1 and y_1 = -4$ and by the same way, for K(-2,8). Therefore, $x_2 = -2 while y_2 = 8$ . By substituting these values in equation 1, we can deduce the following

$slope = \frac{y_2 - y_1}{x_2 - x_1} = \frac{8 - (-4)}{-2 - 1} = \frac{8 + 4}{-2 - 1} = \frac{12}{-3} = -4$

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Turn 1 1/5 to improper fraction

Alex17521 [72]

Answer:

Explanation:

Step 1

Multiply the denominator by the whole number

5 × 1 = 5

Step 2

Add the answer from Step 1 to the numerator

5 + 1 = 6

Step 3

Write answer from Step 2 over the denominator

<h2><u>6/5</u></h2><h2><u></u></h2><h2><u>I hope this answer helps you out! Brainliest would be appreciated.</u></h2>

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3 years ago

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma

pickupchik [31]

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

8 0

3 years ago

Read 2 more answers

Darío buys applesauce cups for a family reunion. He needs 23 cups, and he buys them in packs of 6. How many packs does Dario nee

ioda

Answer:

He needs four packs.

Step-by-step explanation:

6*4=24 there is 23 so he will need 4 packs in total.

3 0

3 years ago

Read 2 more answers

Lucas ate a fraction of a pizza. Hugo ate 5/8 of the same pizza. Now there is 1/8 of the pizza left what fraction of pizza did L

MatroZZZ [7]

Answer:

$\frac{2}{8}$

Step-by-step explanation:

In order to solve this equation we will need to use what we know in order to find the answer.

$1=\frac{8}{8}$

$H=\frac{5}{8}$

$R = \frac{1}{8}$

If Huge ate 5/8's of the pizza and 8/8's creates a whole pizza then the question is quite simple. There is only 1/8's remaining after the boys finish their meal but 5/8's of the pizza was already eaten by Hugo meaning Lucas has to eat 2/8's of the pizza in order for there to be only 1/8's of the pizza left which means 2/8's is your answer.

Hope this helps.

5 0

2 years ago

Solve the system below by substitution. Give your answer as an ordered pair.

bearhunter [10]

Work:
2x+5(6x+23)=-13
2x+30x+115=-13
32x=-128
x=-4

y=6(-4)+23
y=-24+23
y=-1

The answer is (-4,-1)

Hopefully this helps!

6 0

3 years ago