7. x=3 is the midpoint between the roots. The other root is x = 2*3 -(-5) = 11.
8a) f(x) = (x +3)^2 -49. The vertex is (-3, -49). The roots are -10, 4.
8b) y = (x+4)^2 -1. The vertex is (-4, -1). The roots are -5, -3.
8c) f(x) = 2(x +3)^2 -34. The vertex is (-3, -34). The roots are -3±√17.
Answer:
5/3 or 10/12
Step-by-step explanation:
Sketch a right
triangle having adjacent side(A) is given as “3”, hypotenuse side (H) is “x”
and assigning angle “a” as the angle between A and H. Using Pythagorean theorem,
you will get “square root of x-squared minus 9” as the opposite side (O). Using
SOH CAH TOA function, and since secant is the reciprocal of cosine, sec(a) =
x/3. Thus, a = arcsec(x/3). The remaining expression tan(a) is Opposite side
over Adjacent side which is equal to “square root of x^2 - 9” over "3". Therefore, the
algebraic expression would be: tan(arcsec(x/3)) = “sqrt (x^2 -9)” /3. Different answers can be made depending on which side you consider the “3” and “x”.
Answer:
Your question is not correct.
Answer:
AB = 6
Step-by-step explanation:
Since AB is parallel to CD the lengths would be the same amount.
