Answer:
Perimeter of given regular hexagon is <em>48.5 ft</em>.
Step-by-step explanation:
Let <em>ABCDEF</em> be the regular hexagon as shown in the attached figure.
<em>O</em> be the intersection point of the diagonals <em>EB</em>, <em>FC </em>and <em>AD</em>.
As per the property of regular hexagon, all the 6 triangles formed are equilateral triangles.
In other words,
are equilateral 
.
Area of an equilateral 
is defined as
:
Where <em>a </em>is the side of .
Area of hexagon = 
We are given that area of hexagon = 169.74 
Let <em>s </em>be the side of hexagon.
A regular Hexagon is made up of 6 equal sides, so
Perimeter of a regular hexagon = 
Perimeter = 
So, perimeter of given regular hexagon is 
.
Answer:
A. −19z − 77
Step-by-step explanation:
−9(z + 3) − 5(2z + 10)
The first step is to distribute
-9*z -9*3 -5*2z -5*10
-9z-27 -10z-50
-19z -77
9x-72=
9÷9= 1
72÷9=8
so... x-8
Answer:
A-There is no solution
Step-by-step explanation:
There are no values of x
HOPE THIS HELP!!!1
Answer:
<em><u>x=2, y=4</u></em> (as a point,) (2, 4) (last part is unnecessary unless you are graphing)
Step-by-step explanation:
Use substitution.
Substitute y for 2x.
Since y=2x, you can plug 2x into the place where y goes...
Instead of y=-1/2x+5
2x=-1/2x+5....Now solve
2.5x=5 (Sorry my computer cannot type fractions very clearly)
/2.5 /2.5 (dividing by 2.5 on both sides)
<u><em>x=2</em></u>
Now just plug x into any of the equations to find y (preferably the easier one).
y=2x becomes
y=2*(2)
=4
<em><u>y=4</u></em>
