The number is 1/6. 15 minus 3 = 12. 12 times 1/6 is 2
Let
n-------> the number of nickels
q------> the number of quarters
we know that
so
----> equation A
----> equation B
substitute equation B in equation A
![0.05n+0.25[3n]=1.60](https://tex.z-dn.net/?f=0.05n%2B0.25%5B3n%5D%3D1.60)
Find the value of q
therefore
<u>The answer part a) is</u>
the number of nickels are 
and the number of quarters are 
<u>the answer Part b) is</u>
The expressions that represents the number of quarters is
Answer: 128.86cm²
Step-by-step explanation:
The circle is inscribed in the rectangle. To find the shaded portion, subtract he area of the circle from the are of the rectangle.
Area of the rectangle = 11 x 12
= 132cm²
Area of the circle with radius of 1cm = πr²
= 3.142 x 1²
= 3.142cm²
Therefore , area of the shaded region = 132cm² - 3.142cm²
= 128.86cm²
Answer: D
Step-by-step explanation:
Consider the first equation. Subtract 3x from both sides.
y−3x=−2
Consider the second equation. Subtract x from both sides.
y−2−x=0
Add 2 to both sides. Anything plus zero gives itself.
y−x=2
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
y−3x=−2,y−x=2
Choose one of the equations and solve it for y by isolating y on the left hand side of the equal sign.
y−3x=−2
Add 3x to both sides of the equation.
y=3x−2
Substitute 3x−2 for y in the other equation, y−x=2.
3x−2−x=2
Add 3x to −x.
2x−2=2
Add 2 to both sides of the equation.
2x=4
Divide both sides by 2.
x=2
Substitute 2 for x in y=3x−2. Because the resulting equation contains only one variable, you can solve for y directly.
y=3×2−2
Multiply 3 times 2.
y=6−2
Add −2 to 6.
y=4
The system is now solved.
y=4,x=2
Answer:
192
Step-by-step explanation:
12.5% is 24.
So 100% will be (100/12.5) x 24 = 192.
Done.
