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2 years ago

What is the perimeter of the figure? 10 m 5 m 4 m. 6 m 5 m

Mathematics

2 answers:

kvv77 [185]2 years ago

8 0

Answer:

I'm sorry what figure?

Step-by-step explanation:

DerKrebs [107]2 years ago

7 0

What figure ??????????

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How do I answer this and can you explain it to me

aliya0001 [1]

Answer:

5cm

Step-by-step explanation:

This is a trick question

5 0

2 years ago

In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$

Hence, the required number of ways =27434

5 0

2 years ago

What is the value of a? Blank units

Damm [24]

Answer:

289

a^2 x b^2 = c^2

a = 8 b= 15 c = s

64 + 225 = 289

square root 289 = 17

4 0

3 years ago

PLEASE HELP ASAP!!

Nitella [24]

Answer:

The radius of a sphere is 2 millimeters

The surface area of a sphere is 50.24 square millimeters.

The circumference of the great circle of a sphere is 12.56 millimeters.

Step-by-step explanation:

<u><em>Verify each statement</em></u>

case A) The radius of a sphere is 8 millimeters

The statement is false

we know that

The volume of the sphere is equal to

$V=\frac{4}{3}\pi r^{3}$

we have

$V=100.48/3\ mm^{3}$

$\pi =3.14$

substitute and solve for r

$100.48/3=\frac{4}{3}(3.14)r^{3}$

$r^{3}=(100.48)/(4*3.14)$

$r=2\ mm$

case B) The radius of a sphere is 2 millimeters

The statement is True

(see the case A)

case C) The circumference of the great circle of a sphere is 9.42 square millimeters

The statement is false

The units of the circumference is millimeters not square millimeters

The circumference is equal to

$C=2\pi r$

we have

$r=2\ mm$

$\pi =3.14$

substitute

$C=2(3.14)(2)$

$C=12.56\ mm$

case D) The surface area of a sphere is 50.24 square millimeters.

The statement is True

Because

The surface area of the sphere is equal to

$SA=4\pi r^{2}$

we have

$r=2\ mm$

$\pi =3.14$

substitute

$SA=4(3.14)(2)^{2}$

$SA=50.24\ mm^{2}$

case E) The circumference of the great circle of a sphere is 12.56 millimeters.

The statement is true

see the case C

case F) The surface area of a sphere is 25.12 square millimeters

The statement is false

because the surface area of the sphere is $SA=50.24\ mm^{2}$

see the case D

7 0

3 years ago

Read 2 more answers

The table shows the concentration of a reactant in the reaction mixture over a period of time.

saveliy_v [14]

<h3>Option C</h3><h3>The average rate of the reaction over the entire course of the reaction is: $2.0 \times 10^{-3}$ </h3>

<em><u>Solution:</u></em>

Average rate is the ratio of concentration change to the time taken for the change

$Average\ rate = \frac{ \triangle c }{\triangle t }$

The concentration of the reactants changes 1.8 M to 0.6 M

here, the time interval given is 0 to 580 sec

Therefore,

$Average\ rate = \frac{1.8-0.6}{580} \\\\Average\ rate = \frac{1.2}{580} \\\\Average\ rate \approx 2.0 \times 10^{-3}$

Thus option C is correct

5 0

3 years ago