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4 years ago

Need help....... thx

Mathematics

1 answer:

Blababa [14]4 years ago

5 0

I got 75582.

Explanation:

First, group the 40 identical candies into 20 pairs. It doesn't matter how since the candies are identical. This grouping will ensure that any assigment will contain at least two candies.

Then think of the 20 groups a 20 beads on a string. We are looking to place 11 separators between them to obtain 12 segments, each with a varying number of beads between them. How many ways are there to place 11 separators to 19 potential spaces between beads? The asnwer is $n = {19\choose{11}}=75582$

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suppose Tomas buys a total of 30 baseball and football cards in week 5 . how many of each would he have to buy to keep the same

Charra [1.4K]

Answer:

18 baseball cards
12 football cards

Step-by-step explanation:

The only relationship shown in the table is in week 1, where the ratio of baseball to football cards is ...

baseball : football = 9 : 6

In week 1, the total of these numbers is 15. You want the total in week 5 to be 30, double the total in week 1. So, Thomas needs to purchase double the numbers he purchased in week 1:

18 baseball cards
12 football cards

_____

<em>Comment on the attachment</em>

This table came from another question you posted, a question with no content other than the table. The blue numbers are blanks in the original table that have been filled in so as to keep the same 3:2 proportion in each week. They appear to have no bearing on this question.

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3 years ago

List the 5 equivalent fractions for 2/5

salantis [7]

Answer:

Step-by-step explanation:

2/5= 4/10=8/20=16/40=32/80=64/160

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3 years ago

Read 2 more answers

An Undergraduate Study Committee of 6 members at a major university is to be formed from a pool of faculty of 18 men and 6 women

Brums [2.3K]

Answer:

5/33649= approx 0.00015

Step-by-step explanation:

Total number of outcomes are C24 6= 24!/(24-6)!/6!=19*20*21*22*23*24/(2*3*4*5*6)= 19*14*22*23

Half of the Committee =3 persons. That mens that number of the women in Commettee=3. 3 women from 6 can be elected C6 3 ways ( outputs)=

6!/3!/3!=4*5*6*/2/3=20

So the probability that 3 members of the commettee are women is

P(women=3)= 20/(19*14*22*23)=5/(77*19*23)=5/33649=approx 0.00015

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4 years ago

In the number 9,999.999, how does the 9 in the tenths place compare to the 9 in the place to its right

Aleks04 [339]

It’s ten times the value of the 9 in the tenths place.

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3 years ago

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4 years ago