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Dima020 [189]
3 years ago
6

There were 30 red tailed hawks counted during fqll. This was one-fourth of the hawks counted. How many hawks were not red tailed

?
Mathematics
2 answers:
amid [387]3 years ago
5 0

Answer: 90 hawks counted were not red tail.

Step-by-step explanation: If there were 30 hawks to count for a fourth of the hawks counted to solve you just must include the other 3 counting of 30 hawks resulting within the of the full 120 hawks counted only 30 were red tail.

elena-s [515]3 years ago
5 0

Answer:

120

Step-by-step explanation:

30 x 4 = 120

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Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal
lisabon 2012 [21]

Given the following functions below,

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}

Factorising the denominators of both functions,

Factorising the denominator of f(x),

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}

Factorising the denominator of g(x),

\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}

Multiplying both functions,

undefined

4 0
1 year ago
An equation is shown below: 3(2x − 7) = 9
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Answer:

1 solution

Step-by-step explanation:

3(2x-7)=9

dustribute: (3)(2)+(3)(-7x)=9

6+-21x=9

subtract 6 from both sides: -21x=3

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so your 1 solution is x = - 1/7

3 0
2 years ago
I have to write on this question what do I put?
Genrish500 [490]

Answer: 1. Given

2. Corresponding angles

3. Alternate interior angles theorem

4.Corresponding angles

5.Alternate exterior angles

8 0
3 years ago
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