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liubo4ka [24]
3 years ago
6

30 Points for anyone HELP FAST PLEASE

Mathematics
2 answers:
ozzi3 years ago
7 0
Area of triangle = 1/2*(6)(8)
Area of triangle = 1/2*48
Area of triangle = 24 sq ft
Area of half circle = 1/2* π*4^2
Area of half circle = 8 π sqft
Area total = 24+8 π
Area total = 49.12 sq ft
Rashid [163]3 years ago
4 0

Answer:

49,12 ft²

Step-by-step explanation:

r = d/2 = 8ft/2 = 4 ft

A = At + Ac/2

= b×h/2 + π·r²/2

= 6ft×8ft/2 + 3,14·(4ft)²/2

= 3ft×8ft + 3,14×16ft²/2

= 24ft² + 25,12ft²

= 49,12 ft²

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Help ASAP i'll mark u brainliest pls
Lena [83]

Answer:

About <em>4 hours.</em>

Step-by-step explanation:

To find the answer we will <em>add both percentages</em> of <u><em>Watching TV</em></u> and <u><em>Homework</em></u>.  8% + 13% = <em>21%</em>.  Now we will <em>divide 100 by 21</em> and we get<em> 4 hours a day.</em>

4 0
3 years ago
What is the volume of a hemisphere with a radius of 2.1 m, rounded to the nearest tenth of a cubic meter?
Art [367]

Answer:

The volume of hemisphere is <u>19.4 cubic meter</u>.

Step-by-step explanation:

Given:

A hemisphere is with a radius of 2.1 m.

Now, to find the hemisphere volume with radius 2.1 m.

Radius\ (r) = 2.1 m.

So, we put formula to get the volume of hemisphere:

Volume=\frac{2}{3} \pi r^3\ \ \ \ \ (Taking\ the\ value\ of\ \pi =3.14)\\\\Volume=\frac{2}{3} \times 3.14\times 2.1^3\\\\Volume=\frac{2}{3} \times 3.14\times 9.26\\\\Volume=19.384\ cubic\ meter.

<u><em>Hence, the rounded to the nearest tenth of a cubic meter is 19.4 cubic meter.</em></u>

Therefore, the volume of hemisphere is 19.4 cubic meter.

3 0
3 years ago
In the monthly payment formula , what value would you put for r if the interest rate is 5.7%?
natulia [17]
In the monthly payment formula r is the percentage rate as a decimal.

To turn a percentage into a decimal, move the decimal point 2 places to the left.
 5.7% becomes 0.057

3 0
3 years ago
Read 2 more answers
Which equation could represent the graph shown below?
almond37 [142]

Answer:

y=-\sqrt{x-2}

Step-by-step explanation:

I used an online graphing calculator and process of elimination...

3 0
3 years ago
Read 2 more answers
Find all points on the portion of the plane x+y+z=5 in the first octant at which f(x, y, z) = xy2z2 has a maximum value.
irina1246 [14]
Lagrange multipliers:

L(x,y,z,\lambda)=xy^2z^2+\lambda(x+y+z-5)

L_x=y^2z^2+\lambda=0
L_y=2xyz^2+\lambda=0
L_z=2xy^2z+\lambda=0
L_\lambda=x+y+z-5=0

\lambda=-y^2z^2=-2xyz^2=-2xy^2z

-y^2z^2=-2xyz^2\implies y=2x (if y,z\neq0)

-y^2z^2=-2xy^2z\implies z=2x (if y,z\neq0)

-2xyz^2=-2xy^2z\implies z=y (if x,y,z\neq0)

In the first octant, we assume x,y,z>0, so we can ignore the caveats above. Now,

x+y+z=5\iff x+2x+2x=5x=5\implies x=1\implies y=z=2

so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of f(1,2,2)=16.

We also need to check the boundary of the region, i.e. the intersection of x+y+z=5 with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force f(x,y,z)=0, so the point we found is the only extremum.
4 0
3 years ago
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