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yulyashka [42]
3 years ago
11

PLEASE HELP ME!! Use Element and Pure Substance in the same sentence.

Physics
1 answer:
kati45 [8]3 years ago
5 0
Water is an element and a pure substance as it can not be broken down.
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A car has a mass of 1000 kg and accelerates at 2 meters per second per second. what is the magnitude of the net force exerted on
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F=ma
Therefore the net force = 1000kg × 2 metres per second per second
So F=2000 N
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Hi gir_ls join nkd-mbja-nuj​
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never lol

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Enter an expression in the box to Write the equation of the line perpendicular to y=-3x-1 that passes through the point (3,4).
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A boat is traveling at 80 km/hr. How many hours will it take for the boat to cover a distance of 115 km?
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Answer:

Explanation:

Givens

d = 115 km

r = 80 km/hr

t = ?

Equation

d = r*T

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2 years ago
A package is dropped from an air balloon two times. In the first trial the distance between the balloon and the surface is Hand
enyata [817]

Answer:

<em>The final speed of the second package is twice as much as the final speed of the first package.</em>

Explanation:

<u>Free Fall Motion</u>

If an object is dropped in the air, it starts a vertical movement with an acceleration equal to g=9.8 m/s^2. The speed of the object after a time t is:

v=gt

And the distance traveled downwards is:

\displaystyle y=\frac{gt^2}{2}

If we know the height at which the object was dropped, we can calculate the time it takes to reach the ground by solving the last equation for t:

\displaystyle t=\sqrt{\frac{2y}{g}}

Replacing into the first equation:

\displaystyle v=g\sqrt{\frac{2y}{g}}

Rationalizing:

\displaystyle v=\sqrt{2gy}

Let's call v1 the final speed of the package dropped from a height H. Thus:

\displaystyle v_1=\sqrt{2gH}

Let v2 be the final speed of the package dropped from a height 4H. Thus:

\displaystyle v_2=\sqrt{2g(4H)}

Taking out the square root of 4:

\displaystyle v_2=2\sqrt{2gH}

Dividing v2/v1 we can compare the final speeds:

\displaystyle v_2/v_1=\frac{2\sqrt{2gH}}{\sqrt{2gH}}

Simplifying:

\displaystyle v_2/v_1=2

The final speed of the second package is twice as much as the final speed of the first package.

5 0
3 years ago
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