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3 years ago

I need the evaluation

Physics

1 answer:

GalinKa [24]3 years ago

3 0

Answer:

The maximum torque exerted by the person is, τ = 89.96 kg m² s⁻²

Explanation:

Given data,

The mass of the person riding a bike, m = 54 kg

The radius of rotation of the pedal, r = 17 cm

= 0.17 m

The torque exerted by the person is given by the formula,

τ = F r Sin θ

Where,

θ is the angle between F and R

The maximum torque exerted by the person is at θ = 90°

Therefore,

τ = F r

= m x g x r

= 54 x 9.8 x 0.17

= 89.96 kg m² s⁻²

Hence, the maximum torque exerted by the person is, τ = 89.96 kg m² s⁻²

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E1 = k (-q) / a²

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This field goes to the left, repulsive force

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We use the same equations, but with another distance, for the charge -q the distance is R = R+a and for the charge + q the distance is R = R-a

E1 = k q / (R + a)²

E2 = kq / (R-a)²

Et = kq [1 / (R + a)² + 1 / (R-a)²]

Et= kq {[(R-a)² + (R + a)²] / [(R + a)² (R-a)²]}

Et= kq {2 (R² + a²) / [(R + a)² (R-a)²]}

If we use the condition that R> a we can despise in the patents "a"

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Substituting in the total electric field

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