Having more than one atom in its molecule doesn't make
a substance a compound. It's only a compound if it has
atoms of different elements in its molecule.
Both atoms in an Oxygen molecule are the same element ... Oxygen.
Answer:
The orbital speed of this second satellite is 5195.16 m/s.
Explanation:
Given that,
Orbital radius of first satellite ![r_{1}= 8.20\times10^{7}](https://tex.z-dn.net/?f=r_%7B1%7D%3D%208.20%5Ctimes10%5E%7B7%7D%20)
Orbital radius of second satellite ![r_{2}=7.00\times10^{7}\ m](https://tex.z-dn.net/?f=r_%7B2%7D%3D7.00%5Ctimes10%5E%7B7%7D%5C%20m)
Mass of first satellite ![m_{1}=53.0\ kg](https://tex.z-dn.net/?f=m_%7B1%7D%3D53.0%5C%20kg)
Mass of second satellite ![m_{2}=54.0\ kg](https://tex.z-dn.net/?f=m_%7B2%7D%3D54.0%5C%20kg)
Orbital speed of first satellite = 4800 m/s
We need to calculate the orbital speed of this second satellite
Using formula of orbital speed
![v=\sqrt{\dfrac{GM}{r}}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cdfrac%7BGM%7D%7Br%7D%7D)
From this relation,
![v_{1}\propto\dfrac{1}{\sqrt{r}}](https://tex.z-dn.net/?f=v_%7B1%7D%5Cpropto%5Cdfrac%7B1%7D%7B%5Csqrt%7Br%7D%7D)
Now, ![\dfrac{v_{1}}{v_{2}}=\sqrt{\dfrac{r_{2}}{r_{1}}}](https://tex.z-dn.net/?f=%5Cdfrac%7Bv_%7B1%7D%7D%7Bv_%7B2%7D%7D%3D%5Csqrt%7B%5Cdfrac%7Br_%7B2%7D%7D%7Br_%7B1%7D%7D%7D)
![v_{2}=v_{1}\times\sqrt{\dfrac{r_{1}}{r_{2}}}](https://tex.z-dn.net/?f=v_%7B2%7D%3Dv_%7B1%7D%5Ctimes%5Csqrt%7B%5Cdfrac%7Br_%7B1%7D%7D%7Br_%7B2%7D%7D%7D)
Put the value into the formula
![v_{2}=4800\times\sqrt{\dfrac{ 8.20\times10^{7}}{7.00\times10^{7}}}](https://tex.z-dn.net/?f=v_%7B2%7D%3D4800%5Ctimes%5Csqrt%7B%5Cdfrac%7B%208.20%5Ctimes10%5E%7B7%7D%7D%7B7.00%5Ctimes10%5E%7B7%7D%7D%7D)
![v_{2}=5195.16\ m/s](https://tex.z-dn.net/?f=v_%7B2%7D%3D5195.16%5C%20m%2Fs)
Hence, The orbital speed of this second satellite is 5195.16 m/s.
Answer:
Workdone = 465766038 Joules.
Explanation:
<u>Given the following data;</u>
Mass = 1167
Initial velocity = 10m/s
Final velocity =28m/s
To find the workdone;
We know that from the workdone theorem, the workdone by an object or a body is directly proportional to the kinetic energy possessed by the object due to its motion.
Mathematically, it is given by the equation;
W = Kf - Ki
W = ½MVf² - ½MVi²
Substituting into the equation
W = ½(1167)*28² - ½(1167)*10²
W = ½ * 1361889* 784 - ½ * 1361889 * 100
W = 533860488 - 68094450
Workdone = 465766038 Joules.
If its asking the distance for the 65 db then use a proportion, if otherwise pleas clarify. It sounds like a pretty juicy conversation.