All categories

1 year ago

Which of the following is true of ligand gated sodium ion channels neurons?

1 answer:

6 0

The true statement about ligand gated sodium ion channels in neurons are open in response to chemical messenger and hyperpolarize the membrane.

<h3>What are ligand gated sodium ion channels?</h3>

Ligand gated sodium ion channels are the channels present in the neurons. Ion moves through this channel inside the cell or outside the cell.

Thus, the correct option is a) Open in response to chemical messenger and depolarize the membrane.

Learn more about ligands

brainly.com/question/2980623

#SPJ1

You might be interested in

A 30 cm scale has one end broken. The mark at the broken end is 2.6 cm. How would you use it to measure the length of your penci

lidiya [134]

Answer:

the mark of the broken end is 2.6 cm so, we use the scale from the next full mark i.e. 3cm

Explanation:

we now measure the length of the pencil by keeping the 3 cm mark of the scale at it's left end.

The 3 cm value is then subtracted from the scale reading at the right side end of the pencil to obtain the correct length of the pencil. ✏️

(i i ) place the scale in the contact with object along it's length

(2) Your eyes must be exactly in front of the point where the measurements to be taken.

Hope_it_helps_mga_ka_joiners_mwehehe

6 0

2 years ago

Which element can combine with chlorine to make the best conductor of electricity when in the liquid form?

Svetach [21]

The best and most correct answer among the choices provided by your question is the third choice or letter C.

Lithium is the element that can combine with chlorine to make the best conductor of electricity when in the liquid form because it has a much lower electronegativity value.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

3 0

2 years ago

I will be so thankful if u answer correctly!!

olga_2 [115]

<h2>Answer:</h2>

(a) 10N

<h2>Explanation:</h2>

The sketch of the two cases has been attached to this response.

Case 1: The box is pushed by a horizontal force F making it to move with constant velocity.

In this case, a frictional force $F_{r}$ is opposing the movement of the box. As shown in the diagram, it can be deduced from Newton's law of motion that;

∑F = ma -------------------(i)

Where;

∑F = effective force acting on the object (box)

m = mass of the object

a = acceleration of the object

∑F = F - $F_{r}$

m = 50kg

a = 0 [At constant velocity, acceleration is zero]

Substitute these values into equation (i) as follows;

F - $F_{r}$ = m x a

F - $F_{r}$ = 50 x 0

F - $F_{r}$ = 0

F = $F_{r}$ -------------------(ii)

Case 2: The box is pushed by a horizontal force 1.5F making it to move with a constant velocity of 0.1m/s²

In this case, the same frictional force $F_{r}$ is opposing the movement of the box.

∑F = 1.5F - $F_{r}$

m = 50kg

a = 0.1m/s²

Substitute these values into equation (i) as follows;

1.5F - $F_{r}$ = m x a

1.5F - $F_{r}$ = 50 x 0.1

1.5F - $F_{r}$ = 5 ---------------------(iii)

Substitute $F_{r}$ = F from equation (ii) into equation (iii) as follows;

1.5F - F = 5

0.5F = 5

F = 5 / 0.5

F = 10N

Therefore, the value of F is 10N

4 0

2 years ago

A solid block of mass m2 = 1.14 kg, at rest on a horizontal frictionless surface, is connected to a relaxed spring (with spring

borishaifa [10]

Answer:

v = 1 m/s

Explanation:

from the principle of conservation of momentum, we have following relation

initial momentum = final momentum

$m_{1}v_{1}+m_{2}v_{2} = (m_{1}+m_{2})v^{2}$

where

m1 = 1.14 kg

v1 = 2.0 m/s

m2 = 1.14 kg

v2 = 0 m/s

putting all value in the above equation

$1.14 *2.0+ 0 =(1.14+1.14)v^{2}$

$v =\frac{1.14*2.0}{1.14+1.14}$

v = 1 m/s

4 0

3 years ago

You are holding a positive charge and there are positive charges of equal magnitude 1 m to your north and 1 m to your east. what

pychu [463]

By holding a positive charge and there are positive charges of equal magnitude 1 m to your north and 1 m to your east. Therefore, the direction of the force on the charge you are holding will be to the southwest.

Let I hold the charge , q at the centre of given co-ordinate system and two positive charge of equal magnitude Q are placed 1 m to my North and 1 m to my South .

now, both the charge are same nature e.g., positive . Let my charge is also positive (well, you can assume negative too , I am considering positive because it makes me easy to solve) then, both charge repel to my charge.

charge Q placed on east is repelling my charge q toward west . similarly charge Q placed on North is repelling my charge q toward south.

Now , use vector for solve it.

vector $F_{net}$ = vector Fe + vector Fn,