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kondor19780726 [428]
3 years ago
12

The diameter of a circle is 19 m. What is the circumference of the circle? Use 3.14 for pi.

Mathematics
1 answer:
Arlecino [84]3 years ago
6 0

Answer:

D) 59.66 m

Step-by-step explanation:

circumference = 19π = 59.66 m

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answer options: 15,16,16,17. (yes there are two 16's on the answer format), i tried making it 98 points because i have 709, but
lord [1]

Answer:

I believe the answer is 17

Step-by-step explanation:

If you count the length of it by counting how many of the tiny squares it is on it is 17.

5 0
3 years ago
Find the solution to quadratic equation X^2+2x+5-0
VladimirAG [237]

Answer:

=x^2+2x+5

Step-by-step explanation:

X^2+2x+5-0

=X^2+2x+5+0

Combine Like Terms:

=X^2+2x+5+0

=(X^2)+(2x)+(5+0)

=X^2+2x+5

Hope this helped!

7 0
3 years ago
Find the value of X or Y so that the line through the points has the given slope. (X, 0) and (4,1); slope: 1/5
Ronch [10]
Point slope formula:
(y₂ -y₁) = m(x₂ - x₁)
(1 - 0) = \frac{1}{5}(4 - X)
1 = \frac{4}{5} - \frac{1}{5} X
\frac{1}{5} =  -\frac{1}{5} X

-1 = X
8 0
3 years ago
An airplane pilot can see the top of a traffic control tower at a 20 degree angle of depression. the airplane is 5,000 feet away
daser333 [38]

The given question describes a right triangle with with one of the angles as 20 degrees and the side adjacent to the angle 20 degrees is of length 5,000 feet. We are looking for the length of the side opposite the angle 20 degrees.

Let the required length be x, then

\tan{20^o}=\cfrac{opp}{hyp}=\cfrac{x}{5,000}\\ \\ \Rightarrow x=5,000\tan{20^o}=1,819.85

Therefore, the height of the airplane above the tower is 1,819.85 feet.

8 0
3 years ago
Read 2 more answers
Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit
coldgirl [10]
Changing the equation into slope form: y = mx + c, where m is the slope [gradient] and c is the y-intercept.

2x+3y=1470
3y = -2x+1470
y= - \frac{2}{3}x+ \frac{1470}{3}
y=- \frac{2}{3}x+490

The gradient is - \frac{2}{3} and y-intercept is at y=490

Graphing y=- \frac{2}{3}x+490 using slope-intercept method:
a) The slope is a negative slope. The line will go 'down hill'
b) The line must pass the point (0, 490)
c) The line will intercept the x-axis at y = 0
    0 = - \frac{2}{3}x+490
    \frac{2}{3}x = 490
    2x = 1470
    x = \frac{1470}{2}
    x = 735
    So, x-intercept is at (735, 0)

The graph of this function is shown below. The intercepts are labelled at:
y = 490
x = 735

-----------------------------------------------------------------------------------------------------------

Next month's profit equation

2x+3y=1593

Rewriting this into slope-equation form

3y = -2x+1593
y=- \frac{2}{3}+ \frac{1593}{3}
y= - \frac{2}{3}+531

The gradient, m, equals to - \frac{2}{3}
The y-intercept, c, equals to 531

The equation still has the same gradient with last month's profit equation but different y-intercept. 

-------------------------------------------------------------------------------------------------------------

A linear graph show points of (0, 300) and (450, 0)

We work out the slope: 
\frac{300-0}{0-450} = \frac{300}{-450}=- \frac{20}{30}  =- \frac{2}{3}


Y-intercept at x = 0, so it's at y = 300

Equation y = - \frac{2}{3}+300

6 0
3 years ago
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