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3 years ago

Help pleaseeeeeeeeeeeeee

Mathematics

2 answers:

Aleksandr-060686 [28]3 years ago

6 0

-2(9+32n) dhdhshsjsjsjdjdjzjjasjdjd

marin [14]3 years ago

4 0

Answer:

-2(9+32n)

Step-by-step explanation:

Both the 18 and 64 n are negative, and that is the only answer choice that results in two negative numbers.

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The table showing the stock price changes for a sample of 12 companies on a day is contained in the Excel file below.

AfilCa [17]

Answer:

(a) The sample variance for the daily price change is 0.2501.

(b) The sample standard deviation for the daily price change is 0.5001.

Step-by-step explanation:

Let the random variable X denote the stock price changes for a sample of 12 companies on a day.

The data provided is:

X = {0.82 , 1.44 , -0.07 , 0.41 , 0.21 , 1.33 , 0.97 , 0.30 , 0.14 , 0.12 , 0.42 , 0.15}

(a)

The formula to compute the sample variance for the daily price change is:

$s^{2}=\frac{1}{n-1}\sum\limits^{12}_{i=1}{(X_{i}-\bar X)^{2}}$

The sample mean is computed using the formula:

$\bar X=\frac{1}{n}\sum\limits^{12}_{i=1}{X_{i}}$

Consider the Excel output attached below.

In Excel the formula to compute the sample mean and sample variance are:

$\bar X$ =AVERAGE(A2:A13)

$s^{2}$ =VAR.S(A2:A13)

Thus, the sample variance for the daily price change is 0.2501.

(b)

The formula to compute the sample standard deviation for the daily price change is:

$s=\sqrt{\frac{1}{n-1}\sum\limits^{12}_{i=1}{(X_{i}-\bar X)^{2}}}$

Consider the Excel output attached below.

In Excel the formula to compute the sample standard deviation is:

$s$ =STDEV.S(A2:A13)

Thus, the sample standard deviation for the daily price change is 0.5001.

(c)

The (1 - α)% confidence interval for population variance is:

$CI=[\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2} } \leq \sigma^{2}\leq \frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2} } ]$

Compute the critical value of Chi-square for α = 0.05 and (n - 1) = (12 - 1) = 11 degrees of freedom as follows:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2,11}=21.920$

$\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{(1-0.05/2),11}=\chi^{2}_{0.975,11}=3.816$

*Use a Chi-square table.

Compute the 95% confidence interval estimates of the population variance as follows:

$CI=[\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2} } \leq \sigma^{2}\leq \frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2} } ]$

$=[\frac{(12-1)\times 0.2501}{21.920 } \leq \sigma^{2}\leq \frac{(12-1)\times 0.2501}{3.816} ]$

$=[0.125506\leq \sigma^{2}\leq 0.720938]\\\approx [0.1255, 0.7210]$

Thus, the 95% confidence interval estimates of the population variance is (0.1255, 0.7210).

7 0

4 years ago

Text: these two triangles are similar

puteri [66]

Answer:

26.25 cm²

Step-by-step explanation:

The area of the shaded part is the area of the shaded triangle subtract the area of the white triangle.

Since the triangles are similar then the ratios of corresponding sides are equal.

let the height of the white triangle be h, then

$\frac{12}{9}$ = $\frac{10}{h}$ ( cross- multiply )

12h = 90 ( divide both sides by 12 )

h = 7.5

shaded area = $\frac{1}{2}$ × 12 × 10 - $\frac{1}{2}$ × 9 × 7.5 = 60 - 33.75 = 26.25 cm²

5 0

4 years ago

Find the value of x when the triangle has 9 and 3

DENIUS [597]

Answer:

H²=h²+b²

H²=9²+3²

H²=81+9

H²=90

$\sqrt{90}$

5 0

3 years ago

Can someone help me please

postnew [5]

Answer:

1/5

Step-by-step explanation:

8 0

3 years ago

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The number 4432 contains a set of digits in which one digit is 1/10 the value of the other. What are the values of the digits

Vlada [557]

400 is 1/10 of 4000, so the digit is 4

8 0

3 years ago

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