Ligase is<br><br><br> The Gluer<br><br><br> Not sure<br><br><br> The Builder

An electromagnetic wave has a wavelength of 0.12 meters. what is that in nanometers?

tino4ka555 [31]

Answer:

1.2 × 10⁸ m

Explanation:

You want to convert metres to nanometres.

Recall that the multiplying prefix nano- means × 10⁻⁹, so

1 nm = 1 × 10⁻⁹ m

The conversion factor is either $\frac{\text{1 nm} }{10^{-9} \text{m}}$ or $\frac{10^{-9} \text{m} }{\text{1 nm}}$ .

You choose the one that has the desired units (nm) on top. Then

$\lambda = \text{0.12 m} \times \frac{\text{1 nm} }{10^{-9} \text{m}} = 1.2 \times 10^{8} \text{ nm}$

7 0

3 years ago

What is 0.0006250 L in scientific notation

inn [45]

6.250 * 10 to the negative 3

5 0

3 years ago

Read 2 more answers

Electrochemistry - Equilibrium

Ipatiy [6.2K]

Answer:

Explanation:

The relation between equilibrium constant and Ecell is given below .

E⁰cell = (RT / nF ) lnK , F is faraday constant T is 273 + 25 = 298 K

E⁰cell = 1.46 - 1.21 = .25 V

n = 2

Putting the values

.25 = (8.314 x 298 lnK) / (2 x 96485 )

lnK = 19.47

K = 2.85 x 10⁸

2 )

Change in free energy Δ G

Δ G ⁰ = nE⁰ F

n = 4

E⁰ = .4 + .83 = 1.23 V

Δ G ⁰= 4 x 1.23 x 96485

= 474706 J / mol

3 )

E⁰cell = (RT / nF ) lnK

n = 2

1.78 = 8.314 x 298 lnK / 2 x 96485

lnK = 138.638

K = 1.62 x 10⁶⁰

8 0

3 years ago

Determine the number of grams of carbon dioxide that can be formed from 0.500 grams of iron oxide and an excess of carbon.

Nimfa-mama [501]

Taking into account the reaction stoichiometry, 0.2066 grams of CO₂ are formed from 0.500 grams of iron oxide and an excess of carbon.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 Fe₂O₃ + 3 C → 4 Fe + 3 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Fe₂O₃: 2 moles
C: 3 moles
Fe:4 moles
CO₂: 3 moles

The molar mass of the compounds is:

Fe₂O₃: 159.7 g/mole
C: 12 g/mole
Fe: 55.85 g/mole
CO₂: 44 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Fe₂O₃: 2 moles ×159.7 g/mole= 319.4 grams
C: 3 moles ×12 g/mole= 36 grams
Fe: 4 moles ×55.85 g/mole= 223.4 grams
CO₂: 3 moles ×44 g/mole= 132 grams

<h3>Mass of CO₂ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 319.4 grams of Fe₂O₃ form 132 grams of CO₂, 0.500 grams of Fe₂O₃ form how much mass of CO₂?

$mass of CO_{2} =\frac{0.500 grams of Fe_{2}O_{3}x132 grams of CO_{2} }{319.4 grams of Fe_{2}O_{3}}$