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larisa86 [58]
4 years ago
6

How are man-made elements created?

Chemistry
1 answer:
choli [55]4 years ago
3 0
Scientists can by bombarding two lighter elements that together add up to the mass of the desired new element.
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What are function of lipids​
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Lipids serve as structural components of cell membranes, function as energy storehouses, and function as important signalling molecules. They include fats, waxes, oils, hormones, and certain components of membranes and function as energy-storage molecules and chemical messengers.

Hope this helped :)
6 0
2 years ago
If a refrigerator is a heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the
kirill115 [55]
The first law of thermodynamics states the conservation of energy and heat where the <span>total energy in an isolated system may be transformed into another, but never created or destroyed. If 314 J of energy was released to the room, then also 314 J of energy was also removed from food in that refrigerator assuming it is an isolated system. </span>
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3 years ago
What element has a shorthand configuration of [He]2s^22p^1
nlexa [21]

Boron

You start at He and work you way down

3 0
4 years ago
What Household item turns electrical energy into radiant energy
luda_lava [24]

Answer:

Lamps and televisions

Explanation:

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6 0
3 years ago
Read 2 more answers
Determine the ΔH for the following reaction 2NH3 + 5/2O2 = 2NO(g) + 3 H2O(g)
beks73 [17]

The enthalpy change, ΔH for the following reaction 2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g) is -452.76 kJ.

<h3>What is enthalpy change, ΔH, of a reaction?</h3>

The enthalpy change of a reaction is the heat changes that occurs when a reaction proceeds to formation of products.

  • Enthalpy change, ΔH = ΔH of products - ΔH of reactants

The equation of the reaction is given below

2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g)

\Delta{H_{f}\:of\:NO = 90.25 kJ; \Delta{H_{f}\:of\:H_{2}O =-241.82kJ;  \Delta{H_{f}\:of\:NH_{3} =-46.1 kJ;  \Delta{H_{f}\:of\:O_{2} =0

\Delta{H_{f}\:of\:rxn = (90.25*2)+(-241.82*3)-( -46.1*2)= -452.76\:kJ

Therefore, the enthalpy change, ΔH for the following reaction 2\:NH_{3}(g) + \frac{5}{2}\:O_{2}(g)\rightarrow 2\:NO (g) + 3\:H_{2}O (g) is -452.76 kJ.

Learn more about enthalpy change at: brainly.com/question/14047927

#SPJ1

4 0
2 years ago
Read 2 more answers
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