Explain why methyl propyl ether forms both methyl iodide and propyl iodide when it is heated with excess HI.
1 answer:
Answer:
Methyl propyl ether protonates at oxygen, and this makes the oxygen a good leaving group for attack by iodide ion which is a good nucleophile.
We are aware that prefers 1 degree carbocation and here both methyl , propyl group is 1 degree.
So we have two possible carbon atoms to react with iodide which are methyl group and propyl group. They will react with iodide at similar rates, and so there is no great preference of one over the other.
As is present in excess the hydrogen of
protonates the oxygen which leads to cleavage that can happen on both sides either methyl or propyl side leading to different products.
The reaction proceeds in the manner
+
→ CH3I + CH3CH2CH2OH
OR
+
→ CH3OH + CH3CH2CH2I
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The relative age is used in placing sedimentary rocks in order of their occurrence.
To do this, we apply the sedimentary laws.
The ones applicable here are:
- Principle of superposition states that in an undisturbed sequence, the oldest layer is at the base and youngest on top.
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We see that layers 2 and 9 have the same fossil and are the same lithological units.
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Sedimentary rocks brainly.com/question/2740663
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