Answer:
0.96 kg
Step-by-step explanation:
0.56+0.40=0.96
Answer:
The smaller pipe can fill the tank in 6 hours alone.
Step-by-step explanation:
Let us assume that the smaller pipe can fill the tank alone in x hours and the larger pipe fills it in (x - 3) hours.
Therefore, the smaller pipe in 1 hour can fill part of the tank.
Again the larger pipe in 1 hour can fill part of the tank.
So, if both the pipes are open then, in 1 hour they can fill ( part of the tank.
Therefore, they can fill the full tank in hours.
As per given condition, we can write
⇒ x² - 3x = 4x - 6
⇒ x² - 7x + 6 = 0
⇒ (x - 6)(x - 1) = 0
⇒x = 6 or x = 1
But x can not be less than 2 hours.
So, x = 6 hours.
Therefore, the smaller pipe can fill the tank in 6 hours alone. (Answer)
Answer:
(0,12) and (5,0)
Step-by-step explanation:
Since the x is the small pot(5) it would come first when writing it out. And 12 is the large pot(y)
Answer:
Step-by-step explanation:
As it is first order nonlinear ordinary differential equation
Let y(x) = x v(x)
2xy/(x²+y²)=2v/(v^2+1)
dy=xdv+vdx
dy/dx=d(dv/dx)+v
x(dv/dx)+v=(2v)/(v^2+1)
dv/dx=[(2v)/(v^2+1)-v]/x
<h2>∫
= ∫
</h2>
u=v^2
du=2vdv
Left hand side:
∫
=∫
=∫
=
=
Right hand side:
Solve for v:
Answer:
Step-by-step explanation:
The answer is b)
1 + 2 = 3
3 + 1 = 4
12 x 4 = 48
3 4/48
I hope it helps