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3 years ago

Plz Help Brainliest To First Answer In rhombus ABCD , m∠BCE=33∘ . What is m∠ABE ?

Mathematics

1 answer:

Tamiku [17]3 years ago

4 0

Answer:

57 deg

Step-by-step explanation:

Rhombus ABCD has diagonals AC and BD which intersect at point E.

The diagonals of a rhombus divide the rhombus into 4 congruent triangles.

If you find the measures of the angles of one of the triangles, then you know the measures of the angles of all 4 triangles.

Also, the diagonals of a rhombus are perpendicular.

Look at triangle BCE.

m<BCE = 33

m<BEC = 90

m<BCE + m<BEC + m<CBE = 180

33 + 90 + m<CBE = 180

m<CBE = 57

<ABE in triangle ABE corresponds to <CBE in triangle BCE.

m<ABE = m<CBE = 57

Answer: 57 deg

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5. A survey of student pizza preferences showed that 43 students preferred cheese, 56 preferred sausage, 39 preferred pepperoni,

cestrela7 [59]

Answer:

P (Cheese) = 0.199, P (Sausage) = 0.259, P (Pepperoni) = 0.181,

P (Supreme) = 0.130, P (Another Kind) = 0.144

and P (Does not like any kind) = 0.088

Step-by-step explanation:

Given:

Number of students who prefer cheese = 43

Number of students who prefer sausage = 56

Number of students who prefer pepperoni = 39

Number of students who prefer supreme = 28

Number of students who prefer another kind = 31

Number of students who did not like any kind = 19

∴ The total number of students surveyed = $43+56+39+28+31+19=216$ The number of students who prefer pizza = $43+56+39+28+31=197$

The probability that a students likes pizza is,

$P(Student\ likes\ pizza)=\frac{No.\ of\ students\ who\ prefer\ pizza}{Total\ no.\ of\ students\ surveyed}$

$=\frac{197}{216} \\=0.912$

The probability that a students does not likes pizza is,

$P(Student\ does\ not\ likes\ pizza)=\frac{No.\ of\ students\ who\ does\ not\ prefer\ pizza}{Total\ no.\ of\ students\ surveyed}$

$=\frac{19}{216} \\=0.088$

The probability distribution of students who prefer different kinds of pizza is:

The probability that a student likes cheese:

$P(A\ Student\ prefers\ cheese)=\frac{No.\ of\ students\ who\ prefer\ cheese}{Total\ no.\ of\ students\ surveyed}$

$=\frac{43}{216}\\=0.199$

The probability that a student likes sausage:

$P(A\ Student\ prefers\ sausage)=\frac{No.\ of\ students\ who\ prefer\ sausage}{Total\ no.\ of\ students\ surveyed}$

$=\frac{56}{216}\\=0.259$

The probability that a student likes pepperoni:

$P(A\ Student\ prefers\ pepperoni)=\frac{No.\ of\ students\ who\ prefer\ pepperoni}{Total\ no.\ of\ students\ surveyed}$

$=\frac{39}{216}\\=0.181$

The probability that a student likes supreme:

$P(A\ Student\ prefers\ supreme)=\frac{No.\ of\ students\ who\ prefer\ supreme}{Total\ no.\ of\ students\ surveyed}$

$=\frac{28}{216}\\=0.130$

The probability that a student likes another kind:

$P(A\ Student\ prefers\ another\ kind)=\frac{No.\ of\ students\ who\ prefer\ another\ kind}{Total\ no.\ of\ students\ surveyed}$

$=\frac{31}{216}\\=0.144$

Thus, the probability distribution table is displayed below:

6 0

3 years ago

If x = -6,which inequiality is true

zimovet [89]

The only equation that works with x=-6 is A

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3 years ago

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Alex Ar [27]

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Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

(Set up and solve the system, then answer the associated question)

Dimas [21]

9514 1404 393

Answer:

red division: 6 teams
blue division: 5 teams

Step-by-step explanation:

We can let r and b represent the numbers of teams in the red and blue divisions, respectively. The total number of goals scored in each division will be the average for that division times the number of teams in that division.

r - b = 1 . . . . . . there is 1 more red team than blue

4.5r +4.2b = 48 . . . . . . total goals scored per week

Solving by substitution, we have ...

r = b +1

4.5(b +1) +4.2b = 48 . . . . substitute for r

8.7b +4.5 = 48 . . . . . . . . simplify

8.7b = 43.5 . . . . . . . . . . subtract 4.5

b = 43.5/8.7 = 5 . . . . . divide by 8.7

r = b +1 = 6 . . . . . . . . . find r

There are 6 red teams and 5 blue teams.

_____

<em>Additional comment</em>

The basic idea is that you make an equation for each relation given in the problem statement. For a problem like this, you do need to have an understanding of how the average number of goals would be calculated and how that relates to the total goals.

8 0

3 years ago

PLS HELP ASAP FIRST CORRECT ANSWER GETS BRAINLIEST

Anna11 [10]

Using Pythagorean, a^2 + b^2 = c^2
16 +x^2 = 36.69
Then subtract the 16 from 36.69, which is 23.69
And finally take the square root of that, giving you 4.87

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2 years ago