Answer:
The equilibrium concentration of hydrogen gas is 0.0010 M.
Explanation:
The equilibrium constant of the reaction =
}
Moles of hydrogen sulfide = 0.31 mol
Volume of the container = 4.1 L
![[concentration]=\frac{moles}{volume (L)}](https://tex.z-dn.net/?f=%5Bconcentration%5D%3D%5Cfrac%7Bmoles%7D%7Bvolume%20%28L%29%7D)
![[H_2S]=\frac{0.31 mol}{4.1 L}=0.076 M](https://tex.z-dn.net/?f=%5BH_2S%5D%3D%5Cfrac%7B0.31%20mol%7D%7B4.1%20L%7D%3D0.076%20M)

Initially
0.076 M
At equilibrium
(0.076-2x) 2x x
The expression of an equilibrium constant :
![K_c=\frac{[H_2]^2[S_2]}{[H_2S]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2%5D%5E2%5BS_2%5D%7D%7B%5BH_2S%5D%5E2%7D)

Solving for x:
x = 0.00051
The equilibrium concentration of hydrogen gas:
![[H_2]=2x=2\times 0.00051 M=0.0010 M](https://tex.z-dn.net/?f=%5BH_2%5D%3D2x%3D2%5Ctimes%200.00051%20M%3D0.0010%20M)
Answer:
about 0.7 g/mL
Explanation:
Density = mass ÷ volume
D = 5.29 g / (12.6 mL - 5.00 mL)
D = 5.29 g / 7.6 mL
D = 0.696052.... g/mL
D = about 0.7 g/mL
Answer:
We have to fill the acetylene tank with a pressure of 60.67 atm to ensure that you run out of each gas at the same time
Explanation:
Step 1: Data given
Volume of tank 1 = 6.50 L = oxygen
Volume of tank 2 = 4.50 L = acetylene
Pressure in the oxygen tank = 105 atm
Step 2: The balanced equation
2 C2H2 + 5 O2 → 4 CO2 + 2 H2O
For 2 mol C2H2 we need 5 moles O2 to produce 4 moles CO2 and 2 moles H2O
Step 3: Calculate the pressure of the acetylene tank
For 2 mol C2H2 we need 5 moles O2 to produce 4 moles CO2 and 2 moles H2O
This means for each 5 moles O2 we have 2 moles acetylene
Pressure (105 atm) * (2/5) * (6.50 / 4.50) = 60.67 atm
We have to fill the acetylene tank with a pressure of 60.67 atm to ensure that you run out of each gas at the same time
Explanation:
The Watershed
The land that seperates water flowing
Hope this is correct and helpful
HAVE A GOOD DAY!
Grass planting, laying of straw , putting up sediment fenced or knee high black fabric fences can help reduce no point source water pollution