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Advocard [28]
3 years ago
15

Imagine that you have a 6.50 L gas tank and a 4.50 L gas tank. You need to fill one tank with oxygen and the other with acetylen

e to use in conjunction with your welding torch. If you fill the larger tank with oxygen to a pressure of 105 atm , to what pressure should you fill the acetylene tank to ensure that you run out of each gas at the same time
Chemistry
1 answer:
Burka [1]3 years ago
7 0

Answer:

We have to fill the acetylene tank with a pressure of 60.67 atm to ensure that you run out of each gas at the same time

Explanation:

Step 1: Data given

Volume of  tank 1 = 6.50 L = oxygen

Volume of tank 2 = 4.50 L = acetylene

Pressure in the oxygen tank = 105 atm

Step 2: The balanced equation

2 C2H2 + 5 O2 → 4 CO2 + 2 H2O

For 2 mol C2H2 we need 5 moles O2 to produce 4 moles CO2 and 2 moles H2O

 Step 3: Calculate the pressure of the acetylene tank

For 2 mol C2H2 we need 5 moles O2 to produce 4 moles CO2 and 2 moles H2O

This means for each 5 moles O2 we have 2 moles acetylene

Pressure (105 atm) * (2/5) * (6.50 / 4.50) = 60.67 atm

We have to fill the acetylene tank with a pressure of 60.67 atm to ensure that you run out of each gas at the same time

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