You can use the regrouping
4x²+4x-35=0
factor: (2x+7)(2x-5)=0
2x+7=0, or 2x-5=0
2x=-7 or 2x=5
x=-3.5 or x=2.5
I don't see any rounding necessary in this case.
when you factor ax²+bx+c, you take the two factors of a and the two factors of c, one factor of a times one factor of c, the other factor of a times the other factors, the sum of the two products make b.
in this case, the factors of 4 is 2 and 2, the factors of -35 is -5 and 7. I line them up in the following way:
2 -5
2 7
then I multiple them diagonally, the top left 2 multiplying the bottom right 7=14, and the other 2 multiplying -5=-10, 14 and -10 make a sum of 4.
if you don't get the desired sum, switch the factors up and down till you have the right combination. Note: Do not switch left and right.
I hope this makes sense to you.
Answer:
Step-by-step explanation:
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Hope this helps :)
Answer:
17.3
Step-by-step explanation:
To solve this equation, you need to use the pythagorean theorem which is:
a= length
b= height
c= hypotenuse
First, substitute in your values for the equation:
Then, use the squares in the equation:
Then, subtract 100 from both sides to isolate b:
Finally, square root both sides to get your answer:
Then round to the nearest tenth which gives you 17.3.
N^2-3n-4=0
(n-4)(n+1)
-4+1=-3
-4*1=-4
n-4=0
n=4
n+1=0
n=-1
Final answers: x=-1, x=4
