Answer:
<em>-1</em>
Step-by-step explanation:
1. A water wheel rung’s height as a function of time can be modeled by the equation:
h - 8 = -9 sin6t
(b) Determine the maximum height above the water for a rung.
Given the rung's height modeled by the equation;
h - 8 = -9 sin6t
h(t) = -9sin6t + 8
At maximum height, the velocity of the rung is zero;
dh/dt = 0
dh/dt = -54cos6t
-54cos6t = 0
cos6t = 0/-54
cos6t = 0
6t = cos^-1(0)
6t = 90
t = 90/6
t= 15
Substitute t = 15 into the expression to get the maximum height;
Recall:
h(t) = -9sin6t + 8
h(15) = -9sin6(15) + 8
h(15) = -9sin90 + 8
h(15) = -9(1)+8
h(15) = -9+8
<em>h(15) = -1</em>
<em>hence the maximum height above the water is -1</em>
1. The domain of a sqrt(x) is x > 0. So, L > 0.
2. The range of a S(x) = sqrt(x) is S(x) > 0 for all valid x > 0.
Answer:
179.168
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
Answer:
the pole is 24 feet tall
Step-by-step explanation:
the mirror make every thing half its size
