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miv72 [106K]
2 years ago
10

Can you please help me on this question on the picture.I need This answer Asap

Mathematics
1 answer:
oee [108]2 years ago
6 0
For the first one is they are adding by 3's
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Please answer seriously!!
Sedaia [141]

Answer:

27. chord

28. radius

29. diameter

30. secant

31. tangent

32. secant

Step-by-step explanation:

I guess thats the correct answer

6 0
2 years ago
BRAINLIEST ASAP! PLEASE HELP ME :)
Irina-Kira [14]

Answer:

○ \displaystyle 25\%

Step-by-step explanation:

3 → 13 − 16

\displaystyle \frac{Number\:of\:desired\:[favourable]\:outcomes}{Total\:number\:of\:possible\:outcomes} \\ \\ \frac{3}{12} = \frac{1}{4} = 25\%

I am joyous to assist you anytime.

4 0
3 years ago
11.65×0.23 helpppp plssss
Yanka [14]

Answer:

2.6795

Step-by-step explanation:

Just ask! :)

(✿◡‿◡) HAPPY HOLIDAYS!!!

7 0
2 years ago
Read 2 more answers
Which table represents a linear function
lesya692 [45]

Answer: B

Step-by-step explanation:

B is the only one of the tables that goes up with a order

3 0
2 years ago
The antibiotic clarithromycin is eliminated from the body according to the formula A(t) = 500e−0.1386t, where A is the amount re
PolarNik [594]

Answer:

Time(t) = 11.61 hours (Rounded to two decimal place)

Step-by-step explanation:

Given: The antibiotic  clarithromycin is eliminated from the body according to the formula:

A(t) = 500e^{-0.1386t}                 ......[1]

where;

A - Amount remaining in the body(in milligram)

t - time in hours after the drug reaches peak concentration.

Given: Amount of drug in the body is reduced to 100 milligrams.

then,

Substitute the value of A = 100 milligrams in [1] we get;

100= 500e^{-0.1386t}

Divide both sides by 500 we get;

\frac{100}{500}=\frac{ 500e^{-0.1386t}}{500}

Simplify:

\frac{1}{5} = e^{-0.1386t}

Taking logarithm both sides with base e, then we have;

\log_e (\frac{1}{5})= \log_e (e^{-0.1386t})

\log_e (\frac{1}{5})=-0.1386t         [ Using \log_e e^a =a ]

or

\log_e (0.2)=-0.1386t

-1.6094379124341 = -0.1386t

 [using value of \log_e (0.2) = -1.6094379124341 ]

then;

t = \frac{-1.6094379124341}{-0.1386}

Simplify:

t ≈11.61 hours.

Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams


6 0
2 years ago
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