Answer:
22.86% probability that the persons IQ is between 110 and 130
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

If one person is randomly selected what is the probability that the persons IQ is between 110 and 130
This is the pvalue of Z when X = 130 subtracted by the pvalue of Z when X = 110.
X = 130



has a pvalue of 0.9772
X = 110



has a pvalue of 0.7486
0.9772 - 0.7486 = 0.2286
22.86% probability that the persons IQ is between 110 and 130
Answer:
the answer is 22
Step-by-step explanation:
12,15,22,37,49
since 22 is in the middle its the median (make sure you put the #'s from least to greatest)
Answer:
x + y = 11
10x + 5y = 80
Step-by-step explanation:
Answer:
yes
Step-by-step explanation:
9 can be represented as 9/1, which is the reciprocal of 1/9.