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lina2011 [118]
3 years ago
13

How do you find this remainder?

Mathematics
2 answers:
OleMash [197]3 years ago
6 0

Answer:

the answer is 2

Step-by-step explanation:


makkiz [27]3 years ago
3 0

Answer:

C. 2

Step-by-step explanation:

Look at pic below.

Hope this helps! :)

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Solve for m and n<br> I been stuck on this question for an hour
Crazy boy [7]

Answer:

m = 10 , n = 5\sqrt{2}

Step-by-step explanation:

using the cosine and tangent ratio in the right triangle and the exact values

cos45° = \frac{1}{\sqrt{2} } and tan45° = 1 , then

cos45° = \frac{adjacent}{hypotenuse} = \frac{5\sqrt{2} }{m} = \frac{1}{\sqrt{2} } ( cross- multiply )

m = 5\sqrt{2} × \sqrt{2} = 5 × 2 = 10

-----------------------------------------

tan45° = \frac{opposite}{adjacent} = \frac{n}{5\sqrt{2} } = 1 , then

n = 5\sqrt{2}

3 0
2 years ago
HELP! What is the measure of RST?
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What is the main difference between multiplying fractions and dividing fractions?
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The numbers get smaller in division and larger in multiplying
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Where does the section of the bridge meet ground level? Solve 0 = -x2 + 10x - 8
djverab [1.8K]
In can be less mental effort if the equation is multiplied by -1 first.
.. x^2 -10x +8 = 0
.. x^2 -10x +25 +8 -25 = 0
.. (x -5)^2 = 17
.. x -5 = ±√17
.. x = 5 ±√17

The values of x that satisfy the given equation are
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4 0
3 years ago
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A bank pays 5% interest compounded annually. What principal will grow to $12,000 in 10 years.
makvit [3.9K]
<h3>Answer: 7366.96 dollars</h3>

========================================================

Use the compound interest formula:

A = P(1+r/n)^(n*t)

where in this case,

A = 12000 = amount after t years

P = unknown = deposited amount we want to solve for

r = 0.05 = the decimal form of 5% interest

n = 1 = refers to the compounding frequency (annual)

t = 10 = number of years

-------

Plug all these values into the equation, then solve for P

A = P(1+r/n)^(n*t)

12000 = P(1+0.05/1)^(1*10)

12000 = P(1.05)^(10)

12000 = P(1.62889462677744)

12000 = 1.62889462677744P

1.62889462677744P = 12000

P = 12000/1.62889462677744

P = 7366.95904248911

P = 7366.96

6 0
3 years ago
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