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const2013 [10]
3 years ago
9

Can someone solve this question?

Mathematics
1 answer:
Rom4ik [11]3 years ago
3 0

The triangles are isosceles. The following notation are for the angles. For example ABD is refer to the angle located in the B vertex, formed by the segments AB and BD.

ABD = ADB\\40 + 2ADB = 180\\ADB = 70 = ABD\\

70 +  DBC + 30 = 180\\DBC = 180 - 100 = 80

Then

BCD = BCD\\2BCD + 80 = 180\\BCD = 50



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11 is the value of x. hope this helps you
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What is the sum of the multiples of 6 between 6 and 999?
riadik2000 [5.3K]
Your method is completely correct. The first term will be 6 and each subsequent term can be obtained by adding 6 to the previous one, meaning the common difference is 6. The number of terms is given by the highest number that is divisible by 6 and dividing it by 6; that is 996/6 = 166
Then we simply apply the formula for arithmetic sequence sum:
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7 0
2 years ago
Read 2 more answers
What is mathematics?​
RUDIKE [14]

Answer:

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Step-by-step explanation:

I hope this helps you in any way.Have a great day :)

8 0
3 years ago
Read 2 more answers
-3x-y=-17 4x + 2 y equals 20
ExtremeBDS [4]
-3x - y = -17
4x + 2y = 20

multiply one part of the equation so that we can be able to use the process of elimination.

(-3x - y = -17)2
4x + 2y = 20

Now we have:

-6x -2y = - 34
4x+2y= 20
------------------------
-2x = -14

Divide -2 on both sides.

-2x = -14
/-2       /-2

x = -7.


=============================================

To solve for y, we just have to substitute the value of x to any of the equation given above, that we feel comfortable with. And I'm going to choose this equation: 4x + 2y = 20


4x + 2y = 20

4(-7) + 2y = 20

-28 + 2y = 20

Add 28 on both sides

-28 + 2y = 20
+28          +28
---------------------
2y = 48
/2      /2

y = 24.


The last thing you would do is to check if the answers is correct.
All you have to do is plug in the values of x and y into both equations and see if they equal to one another.

You may have to do this by yourself :P

Anyways, if you have any questions about this topic, feel free to PM me or any other users interested. Thank you for being part of Brainly! Have a nice day!










4 0
2 years ago
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