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koban [17]
3 years ago
15

-10x+5y=0 -4x-6y=54 find the solution of this system of equations

Mathematics
1 answer:
yaroslaw [1]3 years ago
6 0
We have the first equation:
-10x + 5y = zero
we can divide all terms by 5 to get:
-2x + y = zero
This means that:
y = 2x .................> equation I

We now will look at the second equation:
<span>-4x-6y=54
</span>we will substitute with equation I in this equation to get:
<span>-4x-6(2x)=54
-4x - 12x = 54
-16x = 54
x = -3.375

Substitute with the value of x in equation I to get y as follows:
y = 2(3.375) = -6.75

Therefore, for the given system of equations:
x = -3.375
y = -6.75</span>
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3 years ago
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There are 2 roots so the only way to complete the square is,

y=2x^2+8x-9\\y=2[(x^2+4x)]-9\\y=2[(x^2+4x+4)-4]-9\\y=2[(x+2)^2-4]-9\\y=2(x+2)^2-8-9\\y=2(x+2)^2-17

Just factor 2 out of 2x^2+8x (just ignore the -9) then find the number that will make the terms be able to complete the square.

then complete the square and multiply 2 inside the brackets.

subtraction as you already get the vertex form and know how to complete the square.

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3 0
3 years ago
Solve 5x^2 - 7x+2 -0 by completing the square. What are the solutions?
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5(<em>x</em>² - 2 • 7/10 <em>x</em> + (7/10)²) - 49/20 + 2 = 0

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<em>x</em> - 7/10 = ± 3/10

<em>x</em> = 7/10 ± 3/10

<em>x</em> = 10/10 = 1   or   <em>x</em> = 4/10 = 2/5

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3 years ago
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